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statuscvo [17]
3 years ago
5

Protactinium has 516 years of half life how many decays will it go through to become 1/64th of the substance? ,

Chemistry
1 answer:
Ulleksa [173]3 years ago
6 0

Answer:

  • 6 decays

Explanation:

Each half life period reduced the amount of substance by half

  • 64 = 2⁶
  • 1/64 = (1/2)⁶

So 6 of half life cycles or decays will go.

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An outdoor grill has a propane (C3H8) tank that holds 4.8 L of gas at a pressure of 5.5 atm. If all of the gas is transferred in
shtirl [24]

Answer: 0.176 atm

Explanation: Solution attached:

Use Boyle's Law to find the new pressure of the gas.

P1V1 = P2V2

Derive for P2

P2 = P1V1 / V2

= 5.5 atm ( 4.8 L ) / 150 L

= 0.176 atm

4 0
3 years ago
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction 2 NO ( g
enyata [817]

Answer:

ΔG = -61.5 kJ/mol (<u>Spontaneous process</u>)

Explanation:

2 NO (g)  +  O₂  (g)   ⇄  2NO₂ (g)

Let's apply the thermodynamic formula to calculate the ΔG

ΔG = ΔG° + R .T . lnQ

We don't know if the gases are at equilibrium, that's why we apply Q (reaction quotient)

ΔG = - 69 kJ/mol + 8.31x10⁻³ kJ/K.mol . 298K . ln Q

How can we know Q? By the partial pressures (Qp)

P NO = 0.450atm

PO₂ = 0.1 atm

PNO₂ = 0.650 atm

Qp = [NO₂]² / [NO]² . [O₂]

Qp = 0.650² / 0.450² . 0.1 = 20.86

ΔG = - 69 kJ/mol + 8.31x10⁻³ kJ/K.mol . 298K . ln 20.86

ΔG = -61.5 kJ/mol (<u>Spontaneous process</u>)

5 0
3 years ago
What is hydrocabron ​
navik [9.2K]

Answer:

Hydrocarbon is a Compound that is made up of Carbon and Hydrogen .

6 0
3 years ago
What is the density of a substance that has a mass of 20 g and a volume of<br> 10 mL?
Paha777 [63]

Answer:

That unknown substance is water

Explanation:

3 0
2 years ago
Using the van der Waals equation, the pressure in a 22.4 L vessel containing 1.00 mol of neon gas at 100 °C is ________ atm. (a
svetoff [14.1K]

Answer:

The answer to your question is        P = 1.357 atm

Explanation:

Data

Volume = 22.4 L

1 mol

temperature = 100°C

a = 0.211 L² atm

b = 0.0171 L/mol

R = 0.082 atmL/mol°K

Convert temperature to °K

Temperature = 100 + 273

                      = 373°K

Formula

               (P + \frac{a}{v^{2}} )(v - b) = RT

Substitution

               (P + \frac{0.211}{22.4})(22.4 - 0.0171) = (0.082)(373)

Simplify

               (P + 0.0094)(22.3829) = 30.586

Solve for P

                           P + 0.0094 = \frac{30.586}{22.3829}

                           P + 0.0094 = 1.366

                                 P = 1.336 - 0.0094

                                P = 1.357 atm

7 0
3 years ago
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