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irina [24]
3 years ago
12

Temperature (°F)

Chemistry
1 answer:
krok68 [10]3 years ago
6 0

Answer:

5ghz

Explanation: crazy

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You and your friend are pushing a bin of books in the same direction. You are pushing with force of 10 N and your friend is push
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It is 5n , that’s it the difference between the 10n and the 15 n
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3 years ago
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Calculate the concentration of OH- in a solution that contains 3.9 x 10-4 M H3O+ at 25°C. Identify the solution as acidic, basic
aalyn [17]

Answer:

[OH⁻] = 2,6x10⁻¹¹

Acidic

Explanation:

The kw in water is:

2 H₂O(l) ⇄ OH⁻(aq) + H₃O⁺(aq)

kw = [OH⁻] [H₃O⁺] = 1,00x10⁻¹⁴

If concentracion of H₃O⁺ is 3,9x10⁻⁴M:

[OH⁻] [3,9x10⁻⁴M] = 1,00x10⁻¹⁴

<em>[OH⁻] = 2,6x10⁻¹¹</em>

pH is defined as - log[H₃O⁺]. If pH>7,0 the solution is basic, if pH<7,0 solution is acidic, if pH=7,0 solution is neutral.

In this problem,

pH = - log [3,9x10⁻⁴M] = <em>3,4</em>

As pH is < 7.0, the solution is <em>acidic</em>

<em></em>

I hope it helps!

8 0
3 years ago
Water is a covalent compound and doesn’t conduct electricity. With this in
oee [108]
the water wants to give the electricity to you because it doesn't want any more electrons it throws them away and gives them to your body
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3 years ago
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Three separate 3.5g blocks of al, cu, and fe at 25°c each absorb 0.505 kj of heat. which block reaches the highest temperature?
77julia77 [94]

The energy can be shown as:

Q = ms dT

Whereas, m is the mass of block

s is specific heat

dT is change in temperature.

Copper block having the lowest specific heat and thus having the higher change in temperature and therefore having the higher final temperature.

8 0
3 years ago
If 20.0 mL of a 0.0800 M HNO3, 35.0 mL of a 0.0800 M KSCN, and 40.0 mL of a 0.0800 M Fe(NO3)3 are combined, what is the initial
Tems11 [23]

Answer:

0.0295M

Explanation:

As you can see, in the mixture you have KSCN and other compounds. The KSCN in solution is dissolved in K⁺ ions and SCN⁻ ions. That means initial concentration of SCN⁻ ions is the same of KSCN, 0.0800M.

You are adding 35.0mL of this solution and the total volume of the mixture is 20.0mL + 35.0mL + 40.0mL = 95.0mL.

That means you are diluting your solution 95.0mL / 35.0mL = 2.714 times.

And the concentration of SCN⁻ is:

0.0800M / 2.714 =

<h3>0.0295M </h3>

4 0
3 years ago
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