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3 years ago

WHICH ONE!!! ASAP FOR A RETAKE FOR SCIENCE PLS

Physics

1 answer:

aleksandr82 [10.1K]3 years ago

8 0

I’m 95% sure it’s covalent bonds.

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A train is traveling north. it goes 200 km /hr for 2.5 hours how far did the train go.

PSYCHO15rus [73]

<h3>Answer: 500 Kilometers</h3>

Explanation:

The formula for finding distance is: speed × time

We must multiply:

200Km/h × 2.5 hours

This gives you 500 Km.

<u>Remember: the formula to work out the distance - speed x time.</u>

If the train speed is 200 km/h, it travels 200 km/h.

Now, we must multiply 200 by 2.5:

200 x 2.5 = 500

Our answer is 500 Kilometers.

7 0

3 years ago

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What is the change in velocity if the final velocity is 80 mph and the initial velocity is 20 mph? Is the object speeding up or

Dimas [21]

Answer: Δv=vf-vi=80mph-20mph=60mph

7 0

3 years ago

6. Why are there some areas of the country where wind power is not the best option? Explain.

zhuklara [117]

Not all states and parts of the country re suitable for wind power because the weather isnt always stable

6 0

3 years ago

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Dry air is primarily composed of nitrogen. In a classroom demonstration, a physics instructor pours 3.6 L of liquid nitrogen int

neonofarm [45]

Answer:

The value is $V_n = 2.2498 \ m^3$

Explanation:

From the question we are told that

The volume of liquid nitrogen is $V_n = 3.6 \ L= 3.6 *10^{-3} \ m^3$

The density of nitrogen at gaseous form is $\rho_n = 1.2929 \ kg/m^3$ = The dry air at sea level

Generally the density of nitrogen at liquid form is

$\rho _l = 808 \ kg/m^3$

And this is mathematically represented as

$\rho_l = \frac{m}{V_l }$

=> $m = \rho_l * V_l$

Now the density of gaseous nitrogen is

$\rho_n = \frac{m}{V_n }$

=> $m = \rho_n * V_n$

Given that the mass is constant

$\rho_n * V_n = \rho_l * V_l$

$1.2929* V_n = 808 * 3.6*10^{-3}$

=> $V_n = 2.2498 \ m^3$

3 0

3 years ago

If the timber weighs 670 N, calculate its angle of inclination when the water surface is 2.1 m above the pivot. Above what depth

Ymorist [56]

Answer:

Q = 40.1 degrees

Explanation:

Given:

- The weight of the timber W = 670 N

- Water surface level from pivot y = 2.1 m

- The specific density of water Y = 9810 N / m^3

- Dimension of timber = (0.15 x 0.15 x 0.0036) m

Find:

- The angle of inclination Q that the timber makes with the horizontal.

Solution:

- Calculate the Flamboyant Force F_b acting upwards at a distance x along the timber, which is unknown:

F_b = Y * V_timber

F_b = 9810*0.15*0.15*x

F_b = 226.7*x N

- Take static equilibrium conditions for the timber, and take moments about the pivot:

(M)_p = 0

W*0.5*3.6*cos(Q) - x/2 * F_b*cos(Q) = 0

- Plug values in:

670*0.5*3.6 - x^2 * 0.5*226.7 = 0

x^2 = 1206 / 113.35

x = 3.26 m

- Now use the value of x and vertical height y to compute the angle of inclination to be:

sin(Q) = y / x

sin(Q) = 2.1 / 3.26

Q = sin^-1 (0.6441718)

Q = 40.1 degrees

5 0

3 years ago