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Lelechka [254]
2 years ago
5

WHICH ONE!!! ASAP FOR A RETAKE FOR SCIENCE PLS

Physics
1 answer:
aleksandr82 [10.1K]2 years ago
8 0
I’m 95% sure it’s covalent bonds.
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4.
Akimi4 [234]

Answer:

c

Explanation:

plz make me brainliest i have answered

5 0
3 years ago
In what year did the Organization of Petroleum Exporting Countries (OPEC) refuse to sell oil to the U.S. due to political differ
Sedaia [141]
A) 1973 I believe it had something to do with the Arab wars happening at the time
6 0
3 years ago
Which one of the following is NOT a simple machine?
ivann1987 [24]
It is hammer because hammers are not examples of a simple machine
6 0
3 years ago
A piece of wood has mass of 250g and volume of 400cm cubed. what is its density​
Zigmanuir [339]

Answer:

0.625 \: g {cm}^{ - 3}

Explanation:

density \:  =  \frac{mass}{volume} \\  \\  =  \frac{250}{400}   \\  \\  = 0.625 \: g {cm}^{ - 3}

5 0
2 years ago
olivia is taking pictures of the ocean on the edge of a cliff when she accidentally drops her phone. The phone hits the water at
In-s [12.5K]

The cliff is 12.71m tall.

Why?

Before solving the problem, we must remember that the phone was dropped, it means that there is no initial velocity, also, the acceleration acting on the phone is the acceleration due to gravity.

So, to find how tall is the cliff, we can use the following equations:

y=y_o+v_o*t-\frac{1}{2}g*t^{2}\\\\v_f=v_o+g*t

t=\frac{v_f}{g} \\\\t=\frac{-15.75\frac{m}{s}}{-9.81\frac{m}{s^{2}}}=1.61s

Now that we know the time, we can calculate how tall is the cliff:

y=y_o+v_o*t+\frac{1}{2}g*t^{2}\\\\y=0+0*1.61s-\frac{1}{2}*(-9.81\frac{m}{s^{2}})*(1.61s)^{2}\\\\y=12.71m

Hence, we have that the cliff is 12.71m tall.

Have a nice day!

3 0
3 years ago
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