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muminat
3 years ago
12

A buoy is anchored tho the oceanfloor. A large wave approaches the buoy. How will the buoy move as the wave goes by?

Physics
1 answer:
nadezda [96]3 years ago
5 0

Answer:

The buoy will move upwards and downwards and well as left and right

Explanation:

As the wind is storing so had the capability to move the buoy in all directions as it is a light object despite being anchored down

PLEASE GIVE BRAINLIEST AND THANKS :-)

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Alika [10]

Answer:

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Explanation:

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3 years ago
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What is a non-example of Newton's 3rd law of motion?
kirill [66]

Answer:

Unbalanced forces are not examples of Newton's third law because not all opposite reactions are unbalanced forces.

Explanation:

4 0
3 years ago
You are tossing a ball directly up into the air. Before the ball leaves your hand, you are exerting a force directed against the
DaniilM [7]

Answer:

F n = 0.2 N

Explanation:

given,                                      

you are exerting force of 10 N on the ball.

mass of the ball = 1 kg              

acceleration due to gravity  = 9.8 m/s²

normal force on the ball = ?          

normal force is force exerted by the object to counteract the force from other object.                

normal force acting on the ball will be

F n = F - mg                          

F n = 10 - 1 × 9.8                        

F n = 10 -9.8                    

F n = 0.2 N            

Hence, normal force acting on the ball is equal to 0.2 N

7 0
3 years ago
The kinetic energy of a 10 Kg ball rolling at 10 meters per second is how many joules
Ulleksa [173]

Answer: 500 joules

Explanation:

Given that

Mass of ball = 10kg

kinetic energy = ?

velocity of the ball = 10m/s

Kinetic energy is the energy possessed by a moving object. It is measured in joules, and depends on the mass (m) of the object and the velocity (v) by which it moves

i.e K.E = 1/2mv²

K.E = 1/2 x 10kg x (10m/s)²

K.E = 0.5 x 10kg x (10m/s)²

K.E = 5 x 100

K.E = 500 joules

Thus, the kinetic energy of the ball is 500 joules

6 0
3 years ago
On a Saturday afternoon, you decide to pay a neighborhood kid to mow your lawn. The kid usesa manual push lawn mower with a mass
Mars2501 [29]

Answer with Explanation:

We are given that

A.Mass,m=12 kg

\theta=53^{\circ}

\mu_k=0.16

Speed,v=1.5m/s

Net force in x direction must be zero

F_{net}=0

Fsin\theta-f=0

Fsin\theta=f

Net force in y direction

N-mg-Fcos\theta=0

N=mg+Fcos\theta

f=\mu_kN=\mu_k(mg+Fcos\theta)

Fsin\theta=\mu_k(mg+Fcos\theta)

Fsin\theta=\mu_kmg+\mu_kFcos\theta

Fsin\theta-\mu_kFcos\theta=\mu_kmg

F(sin\theta-\mu_kcos\theta)=\mu_kmg

F=\frac{\mu_kmg}{sin\theta-\mu_kcos\theta}

Power,P=Fv

P=\frac{\mu_kmg}{sin\theta-\mu_kcos\theta}v

Where g=9.8m/s^2

B.Substitute the values

P=\frac{0.16\times 12\times 9.8}{sin53-0.16cos53}\times 1.5

P=40.17W

6 0
3 years ago
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