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3 years ago

A buoy is anchored tho the oceanfloor. A large wave approaches the buoy. How will the buoy move as the wave goes by?

Physics

1 answer:

nadezda [96]3 years ago

5 0

Answer:

The buoy will move upwards and downwards and well as left and right

Explanation:

As the wind is storing so had the capability to move the buoy in all directions as it is a light object despite being anchored down

PLEASE GIVE BRAINLIEST AND THANKS :-)

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Jim travelled the first 3 hours of his journey at speed of 60 mph and the remaining 5 hours at 24 mph how long is the whole jour

frosja888 [35]

Distance of first instance = speed * Time
= 60 * 3 = 180 miles

Distance of second instance = speed * Time
= 24 * 5 = 120 miles

So, Total Distance = 180 + 120 = 300 miles

In short, Your Answer would be 300 miles

Hope this helps!

4 0

3 years ago

An ammeter is connected in series with a resistor of unknown resistance R and a DC power supply of known emf e. A student uses t

rosijanka [135]

Answer:

B:The actual power dissipated by the resistor is less than P because the ammeter had some resistance.

Explanation:

Here,power has been calculated using current I and total EMF \ε . So,P=EMF*current= ε I will represent total power dissipated in resistor and ammeter.

Now, this total power P has been dissipated in both resistor and ammeter. So, power dissipated in resistor must be less than P as some power is also dissipated in ammeter because it has non-zero resistance.

So, the answer is B:The actual power dissipated by the resistor is less than P because the ammeter had some resistance.

Note that option A,C and E are ruled out as they state power dissipated by resistor is greater than or equal to P which is false.

Also,option D is ruled out as ammeter is connected in series.

8 0

4 years ago

Steam enters an adiabatic turbine at 6 MPa, 600 ℃, and 80 m/s and leaves at 50 kPa, 100 ℃, and 140 m/s. If the power output of t

lisabon 2012 [21]

Answer:

W(r,out) = 5.81 MW

$\eta$ = 86.1 %

Explanation:

we use here steam table for get value of h1, s1 etc

so use for 6MPa and 600 degree

Enthalphy of steam h1 = 3658.8 kJ/kg

Entropy of steam s 1 is = 7.1693 kJ /kg.K

and

for 50 kPa and 100 degree

Enthalphy of steam h2 = 2682.4 kJ/kg

Entropy of steam s2 is = 7.6953 kJ /kg.K

so we use here energy balance equation that is

$m\times(h1 + \frac{v1^2}{2} = m\times(h2 + \frac{v2^2}{2} + W(out)$ ..............1

put here value and we get m

m = $\frac{5\times1000}{3658.8-2682.4+\frac{80^2-140^2}{2}\times \frac{1}{1000}}$

solve it we get

m = 5.156 kg/s

so by energy balance equation

m $\psi$ 1 = m $\psi$ 2 + W(r,out)

W(r,out) = m( $\psi$ 1 - $\psi$ 2)

W(r,out) = h1 - h2 + ΔKE + ΔPE - To(s1-s2)

W(r,out) = $m[h1-h2+ \frac{v1^2-v^2}{2}- To (s1-s2)$

W(r,out) = W(a,out) - m.To.(s1-s2) ........................2

put here value

W(r,out) = 5000 - ( 5.156 × (25 + 273) ×( 7.1693 - 7.6953)

W(r,out) = 5908.19 = 5.81 MW

and

second law deficiency is

$\eta$ = $\frac{W(a,out)}{W(r,out)}$ ..............................3

put here value

$\eta$ = \frac{5}{5.81}

$\eta$ = 86.1 %

6 0

3 years ago

Using a simple machine, a student is able to lift a 500N weight by applying only 100N. What is the mechanical advantage of the s

Vanyuwa [196]

Answer:

The answer is 5

Explanation:

4 0

4 years ago

a chemical reaction a temperature change may occur because of the breaking or formation of chemical bonds that release excess en

Hoochie [10]

Answer:

it cannot be considered a physical change because it occur from the chemical reaction.

Explanation:

because physical change is the change of the size,volume, density,flexibility. in other words its a change in the outer appearance or change in which we can see or feel without using a tool or a machine

hope it help just my opinion

5 0

4 years ago