Solution:
54 / 9 = 6 boxes.
Hi there!
We can begin by calculating the distance remaining after the reaction time.
Δd = vt
Calculate the distance traveled within this time:
Δd = (16)(.79) = 12.64 m
Subtract from the total distance:
150 - 12.64 = 137.66 m remaining
We can use the following equation to solve for the acceleration necessary:
vf² = vi² + 2ad, where vf = 0 since the train will have slowed down to rest.
Rearrange in terms of "a":
0 = vi² + 2ad
(-vi²) = 2ad
(-vi²)/2d = a
Plug in the given values:
(-(16²))/2(137.66) = a
-256/275.32 = -.9298 m/s²
Answer:
Charge,
Explanation:
A moving particle encounters an external electric field that decreases its kinetic energy from 9650 eV to 8900 eV as the particle moves from position A to position B The electric potential at A is 56.0 V and that at B is 19.0 V. We need to find the charge of the particle.
It can be calculated using conservation of energy as :
q = -20.27 e
Hence, this is the required solution.
Speed=distance/time
distance = 10,000 m
time= 27 min 30.42s but we need to convert that completely to seconds
(27x60)+30.42= 1650.12 rounded to 1650
speed=10,000/1650.12
speed=6.059063
Because when we do sig dig we round to the least number of digits we would round to 4 because 1650.12 gets rounded to 1650
so 6.059 m/s
Answer:
a) 65 N
b) Each initially applied a force bigger than static friction to get the box moving and accelerating, then when the desired final speed was achieved they reduced the force to make the net force zero.
Explanation:
a) Here, both boxes are identical. They have different velocities but the velocities are constant hence the force Alice is applying is 65 N. Constant velocity means there is no acceleration.
b) The acceleration that Alice provided must have been different than that of Bob. But after reaching their desired speed they stopped accelerating. This would make the net force zero.