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vesna_86 [32]
3 years ago
11

A gay cylinder what are the variables in gay-lussacs law

Chemistry
2 answers:
Tresset [83]3 years ago
8 0

Gay-Lussac's law of pressure–temperature states that the pressure of a fixed mass of gas is directly proportional to its absolute temperature, when the volume is kept constant.

P/T = K

where P, T and K are pressure, temperature and proportionality constant respectively

Therefore, the variables in Gay-Lussac's law are pressure of the gas and its absolute temperature.


wariber [46]3 years ago
4 0

Answer:

the variables in Gay-Lussac's law are pressure of the gas and its absolute temperature

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lina2011 [118]

Opinions are differ from facts as that we cannot change the facts but opinions can be changed as in first example it is given anthracite is better than bituminous coal may be there is another coal which is more better than anthracite. So here opinion is changed.

<h3>What is Coal ?</h3>

It is a black or brownish black sedimentary rock. It contains Sulphur, hydrogen, oxygen, carbon etc. It is always preferred as fuel. Coal was formed millions years ago when plant decay in the soil. It is obtained from dead vegetation. It is obtained from dead plants matter decay into peat and then it is converted into the coal by the process of heat.

<h3>What is Solar System ?</h3>

Solar System is made up of all the planets that revolve around our Sun. Solar System contains eight planets. These planets are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus and Neptune.

Thus from the above conclusion we can say that Opinions are differ from facts as that we cannot change the facts but opinions can be changed as in first example it is given anthracite is better than bituminous coal may be there is another coal which is more better than anthracite. So here opinion is changed.

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8 0
2 years ago
I need help can someone please do so?
larisa86 [58]

Answer:

0.296 J/g°C

Explanation:

Step 1:

Data obtained from the question.

Mass (M) =35g

Heat Absorbed (Q) = 1606 J

Initial temperature (T1) = 10°C

Final temperature (T2) = 165°C

Change in temperature (ΔT) = T2 – T1 = 165°C – 10°C = 155°C

Specific heat capacity (C) =..?

Step 2:

Determination of the specific heat capacity of iron.

Q = MCΔT

C = Q/MΔT

C = 1606 / (35 x 155)

C = 0.296 J/g°C

Therefore, the specific heat capacity of iron is 0.296 J/g°C

8 0
3 years ago
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