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adelina 88 [10]
3 years ago
13

The ratification of the covenant in Deuteronomy 27-30 includes ________. A. Covenant blessings and curses B. Messianic promises

C. Instructions for priests
Chemistry
1 answer:
mamaluj [8]3 years ago
4 0

Answer:Covenant blessings and curses

Explanation:

The scripture quoted in Deuteronomy 27-30 was Moses's ratification of the covenant between God and the people of Israel. He itemized the terms of the covenant and the blessings that follow obedience to the Lord and the curses that follow disobedience to the Lord. It is a statement of blessings and curses.

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Answer:

Its A

Explanation:

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3 years ago
When 2 moles of Fe(s) react with Cl2(g) to form FeCl3(s) according to the following equation, 799 kJ of energy are evolved.
GenaCL600 [577]

Answer:

1. Exothermic.

2. -1598 kJ.

Explanation:

Hello!

1. In this case, according to the reaction, we can infer that 799 kJ of energy are evolved (given off, released) it means that the enthalpy of reaction is negative as the reactants have more energy than the products; which means this is an exothermic reaction.

2. Here, as we know that the enthalpy of reaction is -799 kJ/mol, we can compute the q-value as shown below, considering the reacted 2 moles of solid iron:

q=2mol*-799 kJ/mol\\\\q=-1598kJ

Which means that 1598 kJ of energy are evolved when 2 moles of solid iron react.

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4 0
3 years ago
How many half-lives are required for the concentration of reactant to decrease to 1.56% of its original value?4247.56.56
neonofarm [45]

Answer:

6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

Concentration is decreased to 1.56 % which means that 0.0156 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 0.0156

Thus,

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.0156=e^{-k\times t}

kt = 4.1604

The expression for the half life is:-

Half life = 15.0 hours

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

\frac{4.1604}{t}=\frac {ln\ 2}{t_{1/2}}

t = 6\times t_{1/2}

<u>6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.</u>

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3 years ago
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Balanced equation:

Mg + 2 HNO3 —> Mg(NO3)2 + H2

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2 years ago
How many kinds of atoms are in a pure substance?
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