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salantis [7]
2 years ago
5

what is the freezing point of a 0.195m aqueous solution of K2S? (Report amount to three decimal points)

Chemistry
1 answer:
Solnce55 [7]2 years ago
4 0
The freezing point depression of water is 1.86°C/m.kg 
<span>K2S dissociates: </span>
<span>K2S ↔ 2K+ + S 2- </span>
<span>1mol K2S will produce 3 mol of ions. </span>
<span>Therefore in the freezing point equation: i = 3 </span>
<span>Depression of freezing point = Kf * i* m </span>
<span>Depression of freezing point = 1.86*3*0.195 </span>
<span>Depression of freezing point = 1.088°C </span>
<span>The solution will freeze at - 1.088°C </span>
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