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julia-pushkina [17]

3 years ago

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Can someone help me with this research for the topics plz help. If everything is properly done then I will mark the brainliest a

nswer!!!!

1 answer:

Paha777 [63]3 years ago

5 0

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A solvent typically boils at 125.0∘C and a solution made from that solvent boils at 128.5∘C. If this solvent has a Kb value of 2

elena-s [515]

Answer:

Explanation:

eevdwdvd

8 0

2 years ago

A salt contains only magnesium and one of the halide ions. A 0.0776-g sample of the salt was dissolved in water, and an excess o

sdas [7]

Answer:

The formula of the magnesium halide is MgF₂

Explanation:

All halides, X, produce a salt with Mg with the formula:

MgX₂

<em>-There are 2 moles of the halide ion per mole of Mg-</em>

<em />

With the mass of the MgSO₄ we can find moles of magnesium sulfate = Moles Mg.

With moles of Mg we can know the moles of the halide -1 mole Mg = 2 moles of Halide-

And we can find the mass of Mg in the 0.0776g sample. Subtracting we can find the mass of the halide and, with the mass and moles of the halide we can find its molecular weight and its identity:

<em>Moles MgSO₄ -Molar mass: 120.366g/mol- = Moles Mg:</em>

0.150g * (1mol / 120.366g) = 1.2462x10⁻³ moles Mg

<em>Moles halide:</em>

1.2462x10⁻³ moles Mg * 2 = <em>2.4924x10⁻³ moles Halide</em>

<em>Mass Mg -Molar mass: 24.305g/mol:</em>

1.2462x10⁻³ moles Mg * (24.305g / mol) = 0.0303g Mg

<em>Mass halide:</em>

0.0776g - 0.0303g Mg = <em>0.0473g</em>

<em>Molecular weight of the halide:</em>

0.0473g / 2.4924x10⁻³ moles =

18.98g/mol

This molecular weight is the molecular weight of Fluoride ion, F⁻,

<h3>The formula of the magnesium halide is MgF₂</h3>

6 0

3 years ago

Hydrofluoric acid (HF) can be prepared according to the following equation:

Artemon [7]

Given the balanced equation:

( Reaction type : double replacement)

CaF2 + H2SO4 → CaSO4 + 2HFI

We can determine the number of grams prepared from the quantity of 75.0 H2SO4, and 63.0g of CaF2 by converting these grams to moles per substance.

This can be done by evaluating the atomic mass of each element of the substance, and totaling it to find the molecular mass.

For H2SO4 or hydrogen sulfate it's molecular mass is the sum of the quantity of atomic mass per element. H×2 + S×1 + O×4 = ≈1.01×2 + ≈32.06×1 + ≈16×4 = 2.02 + 32.06 + 64 = 98.08 u (Dalton's or Da) or g / mol.

For CaF2 or calcium fluoride, it's molecular mass adds 1 atomic mass of calcium and 2 atomic masses of fluoride due to the number of atoms.

Ca×1 + F×2 = ≈40.07×1 + ≈19×2 = 40.08 + 38 = 78.07 u (Da or Dalton's) or g / mol.

3 0

3 years ago

Read 2 more answers

How many atoms are in 3.20 moles of carbon

DIA [1.3K]

Answer:

19.264× $10^{23}$ atoms are present in 3.2 moles of carbon.

Explanation:

It is known that one mole of each element is composed of Avagadro's number of atoms. This is same for all the elements in the periodic table.

So, as 1 mole of any element = Avagadro's number of atoms = 6.02× $10^{23}$ atoms

It is as simple as understanding a dozen of anything is equal to 12 pieces of that object.

As here the moles of carbon is given as 3.20 moles, the number of atoms in this mole can be determined as below.

1 mole of carbon = 6.02 × $10^{23}$ atoms

Then, 3.20 moles of carbon = 3.20 × 6.02 × $10^{23}$ atoms

Thus, 19.264× $10^{23}$ atoms are present in 3.2 moles of carbon.

6 0

3 years ago

If an ideal gas has a pressure of 4.03 atm,

kkurt [141]

Answer:

PV=nRT where P=pressure in atm, V=volume is liters, n=numbber of moles, R=gas constant, 0.08206 L-atm/mole KL, and T=temperature in K (273 + C). So (5.67atm)(99.39L)=n(0.08206 L-atm/mol.K)(328.94K), solve for n, the number of moles, n=20.9 moles.

Explanation:

7 0

3 years ago