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3 years ago

The period of a 440 Hertz sound wave is __ seconds. 1/440 1/220 220 440

Physics

1 answer:

Lerok [7]3 years ago

3 0

You said that the frequency is 440 Hz.

Period = 1/frequency = 1/440 of a second .

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Why metals have thermoconductivity higher than ceramic?

Pie

Answer:

Thermal Conductivity Easily Transmits Heat Among Fine Ceramics

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3 years ago

In what year did the Organization of Petroleum Exporting Countries (OPEC) refuse to sell oil to the U.S. due to political differ

Sedaia [141]

A) 1973 I believe it had something to do with the Arab wars happening at the time

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3 years ago

A boy is pulling a cart by a force of 100N. The frictional force experienced by the cart is 20N. The force causing the motion of

Serga [27]

Answer:

3 is right i guss look : 100N-20N=80N

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3 years ago

A wad of clay of mass m1 = 0.49 kg with an initial horizontal velocity v1 = 1.89 m/s hits and adheres to the massless rigid bar

notka56 [123]

Answer:

<h2>The angular velocity just after collision is given as</h2><h2> $\omega = 0.23 rad/s$ </h2><h2>At the time of collision the hinge point will exert net external force on it so linear momentum is not conserved</h2>

Explanation:

As per given figure we know that there is no external torque about hinge point on the system of given mass

So here we will have

$L_i = L_f$

now we can say

$m_1v_1\frac{L}{2} = (m_2L^2 + m_1(\frac{L}{2})^2)\omega$

so we will have

$0.49(1.89)(0.45) = (2.13(0.90)^2 + 0.49(0.45)^2)\omega$

$\omega = 0.23 rad/s$

Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass

So we can use angular momentum conservation about the hinge point

6 0

3 years ago

A large man sits on a four-legged chair with his feet off the floor. The combined mass of the man and chair is 95.0 kg. If the c

Leto [7]

Answer:

Pressure, $P=29.6\times 10^5\ Pa$

Explanation:

It is given that,

Combined mass of the man and the chair, m = 95 kg

Radius of the leg of chair, r = 0.5 cm = 0.005 m

A large man sits on a four-legged chair with his feet off the floor. The force acting per unit area is called the pressure exerted.

$P=\dfrac{F}{A}$

$P=\dfrac{mg}{A}$

Area of 4 legs, A = 4 A

$P=\dfrac{mg}{4\pi r^2}$

$P=\dfrac{95\times 9.8}{4\pi (0.005)^2}$

$P=29.6\times 10^5\ Pa$

So, the pressure each leg exert on the floor is $29.6\times 10^5\ Pa$ . Hence, this is the required solution.

7 0

3 years ago