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abruzzese [7]
3 years ago
11

When is a model used in science?

Physics
1 answer:
Mamont248 [21]3 years ago
8 0
C. Both of the above
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Suppose this comet were to hit the earth at 40000 km/h and fuse with it. by how much would it change our planet's velocity? (the
sattari [20]
  <span>change in velocity = final velocity - initial velocity = v - u 

for comet: 
uc = initial velocity of comet (before impact) 
vc = final velocity of comet 
mc= mass of comet 

uc = 40000 kmph 
vc = ? 
mc= 10 x 10^14 kg 


for probe: 

up = initial velocity of probe (before impact) 
vp = final velocity of probe 
mp= mass of probe 

up= 37000 kmph 
vp= ? 
mp= 372 kg 

Now, 
by principle of conservation of momentum 

(mc x uc) - (mp x up) = (mc x vc) + (mp x vp) 

Since probe is in comet after collision, vp= vc = V 

then, 

(mc x uc) - (mp x up) = V (mc + mp ) 
V = [(mc x uc) - (mp x up)] / (mc + mp ) 

= ((10 × 10^14 × 40000) - (372 × 37000)) ÷ ((10 × 10^14) + 372) 

= ??? 

then, 

change in velocity of the comet = ??? - (40000) = 



</span>
8 0
3 years ago
Which of the following statements is TRUE?
Yuri [45]
Hello there..

<span>Which of the following statements is TRUE?

</span>D. Light waves are electromagnetic waves and sound waves are mechanical waves.
5 0
3 years ago
Read 2 more answers
Every second, the Sun converts about 600 million tons of hydrogen into 596 million tons of helium. The remaining 4 million tons
Whitepunk [10]

Answer:

Converted to an amount of energy equal to 4 million tons times the speed of light squared. ejected into space in a solar wind.

Explanation:

The 4 million tons of mass is converted to the amount of energy that is equal to 4 million tons times the speed of light squared. This energy moves from the sun with the help of solar winds and received by the planets present in the solar system. This solar energy moves in the form of solar radiation because there is no medium for propagation so that's why we can say that the mass is converted into energy that moves in the form of radiation in discrete packets.

4 0
2 years ago
A 2.0 kg particle moves in a circle of radius 3.1 m. As you look down on the plane of its orbit, the particle is initially movin
Ghella [55]

Answer

given,

L(t) = 10 - 3.5 t

mass of particle = 2 Kg

radius of the circle = 3.1 m

a) torque

    τ = \dfrac{dL}{dt}

    τ = \dfrac{d}{dt}(10 - 3.5 t)

    τ = -3.5 N.m

Particle rotates clockwise as i look down the plane. Hence, its angular velocity is downward.

L decreases the angular acceleration upward. so, net torque is upward.

b) Moment of inertia of the particle

    I = m R^2

    I = 2 x 3.1²

    I = 19.22 kg.m²

    L = I ω

    ω = \dfrac{L}{I}

    ω = \dfrac{10 - 3.5 t}{19.22}

    ω = 0.520 - 0.182 t

  A = 0.52 rad/s             B = -0.182 rad/s²

5 0
3 years ago
Read 2 more answers
Assume that an intercontinental ballistic missile goes from rest to a suborbital speed of 6.50 km/s in 60.0 s (the actual speed
olasank [31]

Answer:

Average acceleration is (11.05)g\ m/s^2

Explanation:

It is given that,

Initial velocity, u = 0

Final velocity, v = 6.5 km/s = 6500 m/s

Time taken, t = 60 s

Acceleration, a=\dfrac{v-u}{t}

a=\dfrac{v}{t}  

a=\dfrac{6500\ m/s}{60}  

a=108.33\ m/s^2

Since, g=9.8\ m/s^2

So, a=(11.05)g\ m/s^2

So, the angular acceleration of the missile is (11.05)g\ m/s^2. Hence, this is the required solution.

4 0
3 years ago
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