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denis-greek [22]
3 years ago
13

Who was albert einstien describe his contributions???

Physics
1 answer:
olga nikolaevna [1]3 years ago
6 0

Answer:

Albert Einstein was from Germany he was born theoritical physicist, from childhood only he loved mechanical toys, he was highly gifted in Mathematics, He was a world citizen and a scientific genius too. His contribution were:

1) he developed the theory of relativity

2) he also discovered the process of nuclear fission

3)he developed the quantum theory of specific heat

4)theory of stimulated emission, on which laser device technology is based

5) law of photoelectric effect

hope it helped you :)

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A body, with a volume of 2 m3, weighs 40 kN. Determine its weight when
lana66690 [7]

Answer:

8.8 kN

Explanation:

V = 2 m³, W = 40 kN, SG = 1.59

Bouyant force N = 1.59 * 1000 kg/m³ * 9.81 N/kg * 2 m³ = 31.2 kN

So the weight becomes 40 - 31.2 = 8.8 kN

3 0
2 years ago
a 250g moves eastward along a straight path at a constant velocity of 12 m per second calculate the momentum of the ball ​
lara31 [8.8K]

Explanation:

If two particles are involved in an elastic collision, the velocity of the second particle after collision can be expressed as: v2f=2⋅m1(m2+m1)v1i+(m2−m1)(m2+m1)v2i v 2 f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i .

6 0
2 years ago
The big bang theory is one of the most accepted theories on the origin of the universe because of scientific evidence, such as _
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3 0
3 years ago
Read 2 more answers
In attempting to pull a 1500-kg car out of a ditch, Arnold exerts a force of 300 N for three seconds, Bob exerts a force of 500
SpyIntel [72]

Answer:

Bob provided the greatest impulse.

Explanation:

Given:

Arnold exerts force = 300 N for 3 seconds

Bob exerts force = 500 N for 2 seconds

Cecil exerts force = 200 N for 4 seconds.

Find:

Highest impulse

Computation:

Impulse = Force × TIme

Arnold provides impulse = 300 N × 3 seconds = 900 N/s

Bob provides impulse = 500 N × 2 seconds = 1,000 N/s

Cecil provides impulse = 200 N × 4 seconds = 800 N/s

Therefore, Bob provided the greatest impulse.

8 0
3 years ago
If a drop is to be deflected a distance d = 0.350 mm by the time it reaches the end of the deflection plate, what magnitude of c
Sloan [31]

Answer:

q = 4.87 X 10^ -14 C

Explanation:

As d=0.350 mm

The ink drop will be accelerated by the electric field between the plates:

a = F/m

d = a(D0 / v)^2 / 2 ...... 1

a = qE/m ............... 2

Substituting 2  into 1:

d = (qE/m)(D0 / v)^2 / 2

q = 2mdv^2 / [E(D0)^2]

q = 2(1.00e-11 kg)(3.50e-4 m)(15.0 m/s)^2 / [(7.70e4 N/C)(2.05e-2 m)^2]

q = 4.87e-14 C

6 0
3 years ago
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