Answer:
8.8 kN
Explanation:
V = 2 m³, W = 40 kN, SG = 1.59
Bouyant force N = 1.59 * 1000 kg/m³ * 9.81 N/kg * 2 m³ = 31.2 kN
So the weight becomes 40 - 31.2 = 8.8 kN
Explanation:
If two particles are involved in an elastic collision, the velocity of the second particle after collision can be expressed as: v2f=2⋅m1(m2+m1)v1i+(m2−m1)(m2+m1)v2i v 2 f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i .
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Answer:
Bob provided the greatest impulse.
Explanation:
Given:
Arnold exerts force = 300 N for 3 seconds
Bob exerts force = 500 N for 2 seconds
Cecil exerts force = 200 N for 4 seconds.
Find:
Highest impulse
Computation:
Impulse = Force × TIme
Arnold provides impulse = 300 N × 3 seconds = 900 N/s
Bob provides impulse = 500 N × 2 seconds = 1,000 N/s
Cecil provides impulse = 200 N × 4 seconds = 800 N/s
Therefore, Bob provided the greatest impulse.
Answer:
q = 4.87 X 10^ -14 C
Explanation:
As d=0.350 mm
The ink drop will be accelerated by the electric field between the plates:
a = F/m
d = a(D0 / v)^2 / 2 ...... 1
a = qE/m ............... 2
Substituting 2 into 1:
d = (qE/m)(D0 / v)^2 / 2
q = 2mdv^2 / [E(D0)^2]
q = 2(1.00e-11 kg)(3.50e-4 m)(15.0 m/s)^2 / [(7.70e4 N/C)(2.05e-2 m)^2]
q = 4.87e-14 C