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nignag [31]
4 years ago
11

A light source emits a beam of photons, each of which has a momentum of 2.7 × 10-29 kg·m/s. (a) what is the frequency of the pho

tons? (b) to what region of the electromagnetic spectrum do the photons belong?
Physics
1 answer:
Levart [38]4 years ago
3 0
Nay60rhk60d rxChk rollxn sixtys cubk whkole lotta bk shkxt cuhk 6x10 wxthk a s ona end west c60st
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An object at rest is suddenly broken apart into fragments a and b by an explosion. the fragment a acquires three times the kinet
lbvjy [14]

Momentum will be conserved in one dimension in the explosion.

<span> Given that the fragment a acquires three times the kinetic energy of the fragment b.  
<span>
P</span><span><span>initial </span><span>= p</span></span>final ⇒ 0 =mₐv⁰ₐ+mьv⁰ь= 0 ⇒ v⁰ь = -mₐv⁰ₐ/mь

KE= 3KEь

⇒1/2 mₐv⁰ₐ² = 3 (1/2mьv⁰ь²) 
</span><span>
⇒1/2 mₐv⁰ₐ²  = 3/2 mь(-mₐv⁰ₐ/mь)²

⇒1/2 mₐv⁰ₐ²  = 3/2 mь(mₐ²v⁰ₐ²/mь²)

</span>

⇒1/2 x 2/3 = mₐ/mь= 1/3


<span> <span> Thus the ratio of the masses of the fragments is 1:3.    </span></span>
4 0
4 years ago
In two or more complete sentences, explain how you can prove that the number of degrees that the Moon rotates around the Earth e
PolarNik [594]

Answer:

Follows are the explanation to this question:

Explanation:

In this solution, it is defined that there are two principal motions for the moon, which are its revolution as well as rotation. In such a movement called revolution, its Moon is relocating around the Earth, in which the approximate movement of the moon from around earth has an average movement of about 13.2° per day, or 92 degrees every week, that's once in 27.3 days.

3 0
3 years ago
Read 2 more answers
Which of the following expressions will have units of kg⋅m/s2? Select all that apply, where x is position, v is velocity, m is m
netineya [11]

Answer: m \frac{d}{dt}v_{(t)}

Explanation:

In the image  attached with this answer are shown the given options from which only one is correct.

The correct expression is:

m \frac{d}{dt}v_{(t)}

Because, if we derive velocity v_{t} with respect to time t we will have acceleration a, hence:

m \frac{d}{dt}v_{(t)}=m.a

Where m is the mass with units of kilograms (kg) and a with units of meter per square seconds \frac{m}{s}^{2}, having as a result kg\frac{m}{s}^{2}

The other expressions are incorrect, let’s prove it:

\frac{m}{2} \frac{d}{dx}{(v_{(x)})}^{2}=\frac{m}{2} 2v_{(x)}^{2-1}=mv_{(x)} This result has units of kg\frac{m}{s}

m\frac{d}{dt}a_{(t)}=ma_{(t)}^{1-1}=m This result has units of kg

m\int x_{(t)} dt= m \frac{{(x_{(t)})}^{1+1}}{1+1}+C=m\frac{{(x_{(t)})}^{2}}{2}+C This result has units of kgm^{2} and C is a constant

m\frac{d}{dt}x_{(t)}=mx_{(t)}^{1-1}=m This result has units of kg

m\frac{d}{dt}v_{(t)}=mv_{(t)}^{1-1}=m This result has units of kg

\frac{m}{2}\int {(v_{(t)})}^{2} dt= \frac{m}{2} \frac{{(v_{(t)})}^{2+1}}{2+1}+C=\frac{m}{6} {(v_{(t)})}^{3}+C This result has units of kg \frac{m^{3}}{s^{3}} and C is a constant

m\int a_{(t)} dt= \frac{m {a_{(t)}}^{2}}{2}+C This result has units of kg \frac{m^{2}}{s^{4}} and C is a constant

\frac{m}{2} \frac{d}{dt}{(v_{(x)})}^{2}=0 because v_{(x)} is a constant in this derivation respect to t

m\int v_{(t)} dt= \frac{m {v_{(t)}}^{2}}{2}+C This result has units of kg \frac{m^{2}}{s^{2}} and C is a constant

6 0
3 years ago
Identify the energy transformation in the image
Yuliya22 [10]

Answer:

d one is correct

Explanation:

as the electrical energy in the socket is transferred to the electric tea pot

4 0
2 years ago
Maxwell guessed that visible light was an electromagnetic wave because of its
nadya68 [22]
Becuase of it's speed
3 0
4 years ago
Read 2 more answers
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