The magnetic field at center of circular loops of wire is 3.78 x 10¯⁵ T.
We need to know about the magnetic field at the center of circular loops of wire to solve this problem. The magnetic field at the center can be determined as
B = μ₀ . I / 2r
where B is magnetic field, μ₀ is vacuum permeability (4π×10¯⁷ H/m), I is the current and r is radius.
From the question above, we know that:
r = 4 cm = 0.04 m
I = 1.7 A
By substituting the parameter, we get
B = μ₀ . I / 2r
B = 4π×10¯⁷ . 1.7 / (2.0.04)
B = 2.67 x 10¯⁵ T
Due to the perpendicular plane of loops, the total magnetic field at center will be
Btotal = √(2(B²))
Btotal = √(2(2.67 x 10¯⁵²))
Btotal = 3.78 x 10¯⁵ T
Find more on magnetic field at: brainly.com/question/7802337
#SPJ4
Malleability is the <span>property characterized by the ability to bend.
</span>
Malleability is the quality of something that can be shaped into something else without breaking. It <span>is a physical property of metals that defines the ability to be hammered, pressed, or rolled into thin sheets without being broken.</span>
Answer:
E = 1/2 M V^2 = 1/2 P V since P = M V
E2 / E1 = P2 V2 / (P1 V1)
P2 / P1 = E2 V1 / (E1 V2) = V2^2 V1 / (V1^2 V2) = V2 / V1
E2 / E1 = V2^2 / V1^2
V2 / V1 = (E2 / E1)^1/2
V2 / V1 = (.9)1/2 = .95
The linear momentum would have to decrease by 5%
The statement that describes the error in the work is that the distance must be converted to meters (m).
<h3>FORMULA FOR WORK:</h3>
Work can be calculated by using the following formula:
W = F × d
Where;
- W = work done
- F = force (N)
- d = distance (m)
According to this question, the force is given as 140N and the distance is given as 30cm. The force is calculated as follows:
F = 140N × 30cm = 4200J
This calculation is erroneous because the unit of distance should be converted from cm to meters.
Learn more about work done at: brainly.com/question/3902440
Answer:
Explanation:
Assuming that the pacific plate moved 178 km in 1.76 million years.
s = Distance = 178 km
t = Time taken = 1.76 million years
Speed is given by
The speed of the plate is
