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Answer:
1. It is a good practice to fully define a sketch to avoid having erroneous dimensions on the faces of a solid, this avoids that when it is required to make an assembly with the drawn part appear assembly errors.
2. The 2D sketch should always be done on a plane, so solidworks would ask you to select a plane on which you want to make the sketch, on the other hand, if it is a 3D sketch, solidworks allows you to do it without the need for Select any plane.
Answer:
Explanation:
The line from "On becoming an inventor" that says:
"I found that at college I could get help from my teachers with solving business problems and in learning new techniques for designing new things"
On Becoming an Inventor was by Dean Kamen an American Engineer, Inventor and Businessman
Answer:
LAOD = 6669.86 N
Explanation:
Given data:
width![= 25 mm = 25\times 10^{-3} m](https://tex.z-dn.net/?f=%20%3D%2025%20mm%20%3D%2025%5Ctimes%2010%5E%7B-3%7D%20m)
thickness ![= 6.5 mm = 6.5\times 10^{-3} m](https://tex.z-dn.net/?f=%3D%206.5%20mm%20%3D%206.5%5Ctimes%2010%5E%7B-3%7D%20m)
crack length 2c = 0.5 mm at centre of specimen
![\sigma _{applied} = 1000 N/cross sectional area](https://tex.z-dn.net/?f=%5Csigma%20_%7Bapplied%7D%20%3D%20%201000%20N%2Fcross%20sectional%20area)
stress intensity factor = k will be
![\sigma_{applied} = \frac{1000}{25\times 10^{-3}\times 6.5\times 10^{-3}}](https://tex.z-dn.net/?f=%5Csigma_%7Bapplied%7D%20%3D%20%5Cfrac%7B1000%7D%7B25%5Ctimes%2010%5E%7B-3%7D%5Ctimes%206.5%5Ctimes%2010%5E%7B-3%7D%7D)
![= 6.154\times 10^{6} Pa](https://tex.z-dn.net/?f=%3D%206.154%5Ctimes%2010%5E%7B6%7D%20Pa%20)
we know that
![k =\sigma_{applied} (\sqrt{\pi C})](https://tex.z-dn.net/?f=k%20%3D%5Csigma_%7Bapplied%7D%20%28%5Csqrt%7B%5Cpi%20C%7D%29)
[c =0.5/2 = 2.5*10^{-4}]
K = 0.1724 Mpa m^{1/2} for 1000 load
if
then load will be
![Kc = \sigma _{frac}(\sqrt{\pi C})](https://tex.z-dn.net/?f=Kc%20%3D%20%5Csigma%20_%7Bfrac%7D%28%5Csqrt%7B%5Cpi%20C%7D%29)
![\sigma _{frac} = 41.04 MPa](https://tex.z-dn.net/?f=%5Csigma%20_%7Bfrac%7D%20%3D%2041.04%20MPa)
![load = \sigma _{frac}\times Area](https://tex.z-dn.net/?f=load%20%3D%20%5Csigma%20_%7Bfrac%7D%5Ctimes%20Area)
![load = 41.04 \times 10^6 \times 25\times 10^{-3}\times 6.5\times 10^{-3} N](https://tex.z-dn.net/?f=load%20%3D%2041.04%20%5Ctimes%2010%5E6%20%5Ctimes%2025%5Ctimes%2010%5E%7B-3%7D%5Ctimes%206.5%5Ctimes%2010%5E%7B-3%7D%20N)
LAOD = 6669.86 N