Draw the sequence of BSTs that results when you insert the keys E, A, S, Y, Q, U, E, S, T, I, O, N, in that order into an initia
lly empty tree. And draw the sequence of BSTs that results when you delete the keys from the tree one by one in the order they were inserted. (Note: here your BST should allow duplicate keys).
1 answer:
Answer:
answer is attached
Explanation:
An important special kind of binary tree is the binary search tree (BST). In a BST, each node stores some information including a unique key value, and perhaps some associated data. A binary tree is a BST iff, for every node n in the tree:
All keys in n's left subtree are less than the key in n, and
all keys in n's right subtree are greater than the key in n.
Note: if duplicate keys are allowed, then nodes with values that are equal to the key in node n can be either in n's left subtree or in its right subtree (but not both). In these notes, we will assume that duplicates are not allowed.
Here are some BSTs in which each node just stores an integer key:
You might be interested in
To develop this problem it is necessary to apply the definitions of entropy change within the bodies
The change of entropy in copper would be defined as
Where,
Q= Heat exchange
T = Temperature
For an incompressible substance, the change in the heat exchange is defined as
Where,
m = Mass
c = Specific heat
Replacing in our equation we have that
Since , then
In this way for the change of enthalpy and internal energy you have to
As , then
Therefore the correct option is A. No change at All
Answer:0.646 KJ
Explanation:
Using First law for cycle
For adiabatic process heat transfer is zero and for isothermal process
d(Q)=d(W)
Given
=
=
=
Now we have to find
=
