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Nana76 [90]
3 years ago
10

Draw the sequence of BSTs that results when you insert the keys E, A, S, Y, Q, U, E, S, T, I, O, N, in that order into an initia

lly empty tree. And draw the sequence of BSTs that results when you delete the keys from the tree one by one in the order they were inserted. (Note: here your BST should allow duplicate keys).

Engineering
1 answer:
jek_recluse [69]3 years ago
8 0

Answer:

answer is attached

Explanation:

An important special kind of binary tree is the binary search tree (BST). In a BST, each node stores some information including a unique key value, and perhaps some associated data. A binary tree is a BST iff, for every node n in the tree:

All keys in n's left subtree are less than the key in n, and

all keys in n's right subtree are greater than the key in n.

Note: if duplicate keys are allowed, then nodes with values that are equal to the key in node n can be either in n's left subtree or in its right subtree (but not both). In these notes, we will assume that duplicates are not allowed.

Here are some BSTs in which each node just stores an integer key:

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Answer:

E=52000Hp.h

E=38724920Wh

E=1.028x10^11 ftlb

Explanation:

To solve this problem you must multiply the engine power by the time factor expressed in h / year, to find this value you must perform the conventional unit conversion procedure.

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E=(12.5hp)(\frac{16h}{day} )(\frac{5 days}{week} )(\frac{52week}{year} )\\

E=52000Hp.h

E=52000Hp.h(\frac{744.71Wh}{Hp.h} )\\

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E=52000Hph(\frac{1977378.4  ft lb}{1Hph}

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3 0
3 years ago
A 1000 kg turbine has a rotating unbalance of 0.1 kg.m. The turbine operates at a speed between 500 to 750 rpm. What is the maxi
raketka [301]

Answer:

maximum isolator stiffness k =1764 kN-m

Explanation:

mean speed of rotation =\frac{N_1 +N_2}{2}

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  =65.44 rad/sec

F_T = mw^2 e

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also

transmission ratio = \frac{1}{[\frac{w}{w_n}]^{2} -1}

0.7 =\frac{1}{[\frac{65.44}{w_n}]^2 -1}

SOLVING FOR Wn

Wn = 42 rad/sec

Wn = \sqrt {\frac{k}{m}

k = m*W^2_n

k = 1000*42^2 = 1764 kN-m

k =1764 kN-m

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6 0
3 years ago
In a reversing 2-high mill, a series of cold rolling process is used to reduce the thickness of a plate from 45mm down to 20mm.
podryga [215]

Answer:

Explanation:

Given

Initial Thickness=45 mm

Final thickness=20 mm

Roll diameter=600 mm

Radius(R)=300 mm

coefficient of friction between rolls and strip (\nu)=0.15

maximum draft(d_{max})=\nu ^2R

=0.15^2\times 300=6.75 mm

Minimum no of passes=\frac{45-20}{6.75}=3.70\approx 4

(b)draft per each pass

d=\frac{Initial\ Thickness-Final\ Thickness}{min.\ no.\ of\ passes}

d=\frac{45-20}{4}=6.25 mm

5 0
3 years ago
A 240V single phase 6000 W heavy duty commercial electric heater runs constantly for 36 hours. If electricity cost $0.13/kWh, ho
Aloiza [94]

Answer:

A. $28

Explanation:

We have the load to be 240V

6000W will be converted to kilowatts

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Time heater runs for 36 hours

Cost of electricity = $0.13/Kwh

The question needs us to find cost of running this electric heater

Total kilowatts

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= 216kwh

Then the total cost = 216 x $0.13

= 28.08

= $28

5 0
3 years ago
Read 2 more answers
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