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ASHA 777 [7]
3 years ago
6

The molecular geometry of SO 3 is a. tetrahedral b. bent C. octahedral d. trigonal planar e. pyramidal

Chemistry
1 answer:
dybincka [34]3 years ago
5 0

Answer:

The molecular geometry of SO3 is trigonal planar.

Explanation:

Look at the Lewis

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What is a solution of zinc and copper?<br>five letter word
Lana71 [14]

Answer:

Brass

Explanation:

Brass is an alloy of copper and zinc, in proportions which can be varied to achieve varying mechanical and electrical properties.

5 0
2 years ago
Find the mass of each of these substances? 2.40 mol NaOH
damaskus [11]
Na = 23 x 2.40 = 55.2
O = 16 x 2.40 = 38.4
H = 1 x 2.40 = 2.40

55.2 + 38.4 + 2.4 = 96

2.40 mol of NaOH = 96 amu

4 0
3 years ago
The structural level of a protein least affected by a disruption in hydrogen bonding is the
sergeinik [125]
I think the correct answer from the choices listed above is option A. The structural level of a protein least affected by a disruption in hydrogen bonding is the primary level. The other levels are very much affected by hydrogen bonding. Hope this answers the question.
7 0
3 years ago
How many grams of N2 are in 44.8L at STP?
lutik1710 [3]

Answer: 10 i think

Explanation:

3 0
3 years ago
An atom of a particular element is traveling at 1.00% of the speed of light. The de Broglie wavelength is found to be 3.31 × 10-
ExtremeBDS [4]

Answer:

The given atom is of Ca.

Explanation:

Given data:

Speed of atom = 1% of speed of light

De-broglie wavelength = 3.31×10⁻³ pm (3.31×10⁻³ / 10¹² = 3.31×10⁻¹⁵ m)

What is element = ?

Solution:

Formula:

m = h/λv

m = mass of particle

h  = planks constant

v = speed of particle

λ = wavelength

Now we will put the values in formula.

m = h/λv

m = 6.63×10⁻³⁴kg. m².s⁻¹/3.31×10⁻¹⁵ m ×( 1/100)×3×10⁸ m/s

m = 6.63×10⁻³⁴kg. m².s⁻¹/ 0.099×10⁻⁷m²/s

m = 66.97×10⁻²⁷ Kg/atom

or

6.69×10⁻²⁶ Kg/atom

Now here we will use the Avogadro number.

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

Now in given problem,

6.69×10⁻²⁶ Kg/atom × 6.022 × 10²³ atoms/ mol × 1000 g/ 1kg

40.3×10⁻³×10³g/mol

40.3  g/mol

So the given atom is of Ca.

8 0
2 years ago
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