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ludmilkaskok [199]
3 years ago
15

A 200N force pushes forward on the 20kg truck. The truck pulls two crates connected together by ropes, as shown. The gravitation

al constant is 10N/kg. Determine the acceleration of the crates and truck and the tension in each rope for one of the following sets of conditions.
Please help me! I am really confused on how to draw the diagrams and how to find the x component forms and the unknowns! I've tried working on it but ended up erasing it cause it seemed wrong.

Physics
1 answer:
devlian [24]3 years ago
6 0

Force on left crate, right crate and truck we need to draw here

First we will write the equation for left crate

T_{left} = m*a

T_{left} = 20*a

Now similarly for right crate

T_{right} - T_{left} = 20*a

now for truck

F - T_{right} = 20*a

Now we know that F = 200 N

200 - T_{right} = 20*a

now add all three equation

T_{left} + T_{right} - T_{left} + 200 - T{right} = 20a + 20 a + 20a

200 = 60 a

a = 10/3 m/s^2

now we will find all tension using this value of acceleration

T_{left} = 20 * \frac{10}{3} = \frac{200}{3} N

T_{right} - \frac{200}{3} = 20*\frac{10}{3}

T_{right} = \frac{400}{3} N


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Cloud [144]

Answer:

The net force = 0

Explanation:

The given information includes;

The mass of the crate = 250 kg

The way the helicopter lifts the crate = Uniformly (constant rate (speed), no acceleration)

In order to pull the crate upwards, the helicopter has to provide a force equivalent to the weight of the crate keeping the helicopter on the ground.

The weight of the crate = The mass of the crate × The acceleration due gravity acting on the crate

The weight of the crate, F_w↓ = 250 kg × 9.81 m/s² = 2,452.5 N

The force the helicopter should provide to just lift the crate, F_{(helicopter)}↑ = The weight of the crate = 2,452.5 N

The net force, F_{(net)} = F_{(helicopter)}↑ - F_w↓ = 2,452.5 N - 2,452.5 N = 0

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3 years ago
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ohaa [14]

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Explanation:

Given:-

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- The bulk modulus B of a material is dependent on change in pressure or Force per unit area and change in volume by the following relationship.

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- Now rearrange the above relation and solve for ΔP or force per unit area.

                                  ΔP = B* [(ΔV/V)]

- Plug in the values:

                                  ΔP = (1.6*10^9)*(4 ✕ 10^-3)

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- For unit conversion from N/m^2 to N/cm^2 we have:

                                  ΔP = (6400000 N/m^2) cm^2 / (100)^2 m^2

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hichkok12 [17]
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Source: Bachelor's degree in Physics.
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Hope this helps
May God bless you and your family
8 0
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as you can't destroy the electron or create it - you can't destroy or create charge 

5 0
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