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ludmilkaskok [199]
3 years ago
15

A 200N force pushes forward on the 20kg truck. The truck pulls two crates connected together by ropes, as shown. The gravitation

al constant is 10N/kg. Determine the acceleration of the crates and truck and the tension in each rope for one of the following sets of conditions.
Please help me! I am really confused on how to draw the diagrams and how to find the x component forms and the unknowns! I've tried working on it but ended up erasing it cause it seemed wrong.

Physics
1 answer:
devlian [24]3 years ago
6 0

Force on left crate, right crate and truck we need to draw here

First we will write the equation for left crate

T_{left} = m*a

T_{left} = 20*a

Now similarly for right crate

T_{right} - T_{left} = 20*a

now for truck

F - T_{right} = 20*a

Now we know that F = 200 N

200 - T_{right} = 20*a

now add all three equation

T_{left} + T_{right} - T_{left} + 200 - T{right} = 20a + 20 a + 20a

200 = 60 a

a = 10/3 m/s^2

now we will find all tension using this value of acceleration

T_{left} = 20 * \frac{10}{3} = \frac{200}{3} N

T_{right} - \frac{200}{3} = 20*\frac{10}{3}

T_{right} = \frac{400}{3} N


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denpristay [2]

Answer:

180m to the east

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                --------------------------------------------------------→

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3 years ago
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Answer:

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Hi!

Let C~ = A~ + B~

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|C| = 16.261

cos Ф = 15.65/16.261

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