In a closed system, the loss of momentum of one object is same as________ the gain in momentum of another object
according to law of conservation of momentum, total momentum before and after collision in a closed system in absence of any net external force, remains conserved . that is
total momentum before collision = total momentum after collision
P₁ + P₂ = P'₁ + P'₂
where P₁ and P₂ are momentum before collision for object 1 and object 2 respectively.
P'₁ - P₁ = - (P'₂ - P₂)
so clearly gain in momentum of one object is same as the loss of momentum of other object
Leaning against a brick wall.
All the others use scientific forces of work.
-Steel jelly.
Answer:
DETAILS IN THE QUESTION INSUFFICIENT TO ANSWER
Explanation:
Assuming the liquid to be water ,
the density
of water is :
Buoyant force exerted by a liquid on an object with
of it's volume immersed is :

where ,
is the buoyant force
is the density of the liquid
is the acceleration due to gravity
Thus at equilibrium:

from these , we get the density of brass to be 
which is not possible
1 kg=100000 cg
2 kg=200000 cq
If mass is the quantity then kg is the S.I
2 kg=2kg
<span>You want to focus on the car's acceleration.
(Hope this helps you! :) Have a nice day!)</span>