To solve this problem it is necessary to apply the concepts related to
conservation of energy, for this case manifested through work and kinetic energy.
Where,
F= Force (Frictional at this case 
)
d= Distance
Where,
m = mass
v = velocity
Equation both terms,
Replacing with our values we have that
Therefore the shortest distance in which the truck can come to a halt without causing the crate to slip forward relative to the truck is 49.05m
<u>Answer:</u>
<u>air mass</u>
<u>Explanation:</u>
Remember, the weather of a particular location is often a description of the atmospheric condition of that particular place.
Indeed, the definition of an air mass fits the reporter's description above. As the name implies, <u>a particular air mass would represent the temperature characteristics of a particular area that has a constant or the same temperature and air pressure.</u>
D; it’s north magnetic pole would be pointing toward the geographic south pole
Answer: I believe the right answer would be C
I hope this helps. Correct me if im wrong
Answer:
<h2>100 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 25 × 4
We have the final answer as
<h3>100 J</h3>
Hope this helps you
