Answer:
It can hold up to 
of waste
<em></em>
Step-by-step explanation:
Given
-- Diameter
-- height
Required
Determine the amount of waste it can hold
This simply means that we calculate the volume of the cylindrical container.
And this is calculated using:
Where
and
So, we have:
<em>Hence, it can hold up to </em><em> of waste</em>
Answer:
1)Area; A = ¼πr²
Perimeter; P = πr/2 + 2r
2)A = 19.63 cm²
P = 17.85 cm
3) r = 8.885 cm
4) r = 14 cm
Step-by-step explanation:
This is a quadrant of a circle. Thus;
Area of a circle is πr². A quadrant is a quarter of a circle. Thus;
Formula for Quadrant Area is; A = ¼πr²
A) Perimeter of a circle is 2πr. Thus, perimeter of a quadrant is a quarter of the full circle perimeter.
Formula for the quadrant perimeter in the image given is;
P = 2πr/4 + 2r
P = πr/2 + 2r
B) When r is 5 cm;
A = ¼π(5)²
A = 19.63 cm²
P = π(5)/2 + 2(5)
P = 17.85 cm
C) when A is 100cm²:
¼πr² = 100
r² = 100 × 4/π
r² = 78.9358
r = √78.9358
r = 8.885 cm
D) when P = 50 cm.
50 = πr/2 + 2r
50 = (½π + 2)r
r = 50/(½π + 2)
r = 14 cm
<h3>Answer:</h3><h3>Exact volume =
32pi</h3><h3>Approximate volume =
100.48</h3>
The approximate volume only applies when pi = 3.14
Use either answer, but not both of course.
===============================================
Work Shown:
V = volume of cylinder
V = pi*r^2*h
V = pi*2^2*8
V = pi*32
V = 32pi .... exact volume in terms of pi
V = 32*3.14
V = 100.48 .... approximate volume when we use pi = 3.14
Step-by-step explanation:
4x2 - 25b2
We can solve it by the squares so
(2x - 5b) (2x + 5b)
2) x2 - 81
The same case is here so
(x - 9) (x + 9)
Answer:
53
Step-by-step explanation:
Use pemdas
Use P and do (2+2)
then E 2^3 to get 8
Now you have 9-4/4+8*5
Do M and D To get 9-1+45
Now add and subtract to get your answer
