I bet no one can solve this

Chemistry

1 answer:

Nikitich [7]3 years ago

3 0

The answer is 89.4 g/mol cuz the two units carry positives so that means 8.50 flows for 2 more hours than usual.

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What are intermediates in a reaction? Give an example.

Andrews [41]

In a reaction, molecular entity that is formed from the reactants. For example, consider this hypothetical stepwise reaction: A + B → C + D.

8 0

3 years ago

A 0.10 M aqueous solution of sodium sulfate, Na2SO4, is a better conductor of electricity than a 0.10 M aqueous solution of sodi

Dvinal [7]

Answer: D) More moles of ions are present in a given volume of 0.10 M $Na_2SO_4$ than in the same volume of 0.10 M NaCl.

Explanation:

A electrolyte is a solution that dissociates completely when dissolved in water. The ions act as good conductors of electric current in the solution.

More is the number of ions , more will be the conductance and hence the solution will be a better conductor of electricity.

0.10 M aqueous solution of $Na_2SO_4$ is a better conductor of electricity as it dissociates to give three ions whereas 0.10 M aqueous solution of $NaCl$ dissociates to give two ions only.

$Na_2SO_4\rightarrow 2Na^++SO_4^{2-}$

$NaCl\rightarrow Na^++Cl^{-}$

Thus 0.10 M aqueous solution of sodium sulfate, $Na_2SO_4$ , is a better conductor of electricity as more moles of ions are present in a given volume of 0.10 M $Na_2SO_4$ than in the same volume of 0.10 M $NaCl$

3 0

4 years ago

Use Lewis theory to draw the structure of the compound containing 1 carbon and 4 chlorine atoms. What would you find surrounding

Nikolay [14]

Answer : The correct option is, (B) no double bonds.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

As we are given that the structure of the compound containing 1 carbon and 4 chlorine atoms.

Thus, the molecule is, $CCl_4$

As we know that carbon has '4' valence electrons and chlorine has '7' valence electrons.

Therefore, the total number of valence electrons in $CCl_4$ = 4 + 4(7) = 32

According to Lewis-dot structure, there are 8 number of bonding electrons and 24 number of non-bonding electrons.

From the Lewis-dot structure we conclude that there are 4 single bonds are surrounding the central atom of this ion there is no double or triple bonds are present.

Hence, the correct option is, (B) no double bonds.