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IRISSAK [1]
3 years ago
10

How far does a runner run if he runs for 60 seconds at 5 m/s

Physics
1 answer:
mylen [45]3 years ago
4 0

Answer: 20 miles

Explanation:

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A 1.25 kg block is attached to a spring with spring constant 17.0 N/m . While the block is sitting at rest, a student hits it wi
Free_Kalibri [48]

Answer:

The amplitude of the subsequent oscillations is 13.3 cm

Explanation:

Given;

mass of the block, m = 1.25 kg

spring constant, k = 17 N/m

speed of the block, v = 49 cm/s = 0.49 m/s

To determine the amplitude of the oscillation.

Apply the principle of conservation of energy;

maximum kinetic energy of the stone when hit = maximum potential energy of spring when displaced

K.E_{max} = U_{max}\\\\\frac{1}{2} mv^2 = \frac{1}{2} kA^2\\\\where;\\\\A \ is \ the \ maximum \ displacement = amplitude \\\\mv^2 = kA^2\\\\A^2 = \frac{mv^2}{k} \\\\A = \sqrt{\frac{mv^2}{k}} \\\\A =  \sqrt{\frac{1.25\  \times \ 0.49^2}{17}} \\\\A = 0.133 \ m\\\\A = 13.3 \ cm

Therefore, the amplitude of the subsequent oscillations is 13.3 cm

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3 years ago
Green light travels by what type of wave? (2 points) a Conductive b Electronic c Conducive d Electromagnetic
antiseptic1488 [7]

Answer: d. Electromagnetic wave

Explanation:

Light is an electromagnetic wave, no matter is wavelength or color.

In this sense, the main characteristic of this type of wave is that it can propagate trhough vacumm, it is not necessary a medium. In addition, electromagnetic waves are transversal waves, this means the electric field oscillates in all normal directions to the direction of wave propagation.

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Suppose that a 710 kg car is traveling at 13 m/s. Its brakes can apply a force of 4000 N.
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Answer:lalalalalall

Explanation:

3 0
3 years ago
the maximum displacement of an oscillatory motion is A=0.49m. determine the position x at which the kinetic energy of the partic
kipiarov [429]

Answer:0.4 m

Explanation:

Given

Maximum displacement A=0.49

The sum of kinetic and elastic potential energy is \frac{1}{2}kA^2

where k=spring constant

U+K.E.=\frac{1}{2}kA^2

when K.E.=U/2

K.E.=kinetic energy

U=Elastic potential Energy

\rightarrow \ U+\frac{U}{2}=\frac{1}{2}KA^2\\\rightarrow \ \frac{3U}{2}=\frac{1}{2}KA^2\\\rightarrow \ U=\frac{1}{3}KA^2\\\rightarrow \ \frac{Kx^2}{2}=\frac{1}{3}KA^2\\\\x=\sqrt{\frac{2}{3}}A\\x=0.4\ m

3 0
3 years ago
When electrons are shared unequally a/an<br> bond is formed
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Covalent bonds form when electrons are shared between atoms and are attracted by the nuclei of both atoms. In pure covalent bonds, the electrons are shared equally. In polar covalent bonds, the electrons are shared unequally, as one atom exerts a stronger force of attraction on the electrons than the other.
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