Answer:
a) 
b) The second runner will win
c) d = 10.54m
Explanation:
For part (a):
For part (b) we will calculate the amount of time that takes both runners to cross the finish line:
Since it takes less time to the second runner to cross the finish line, we can say the she won the race.
For part (c), we know how much time it takes the second runner to win, so we just need the position of the first runner in that moment:
X1 = V1*t2 = 239.46m Since the finish line was 250m away:
d = 250m - 239.46m = 10.54m
An example of a a predator in the Ethiopian Highlands ecosystem is the
Wolf.The wolf is a carnivore which acts as a predator to other smaller
animals in the ecosystem.
<h3>What is a Prey?</h3>
Preys are mostly smaller animals in which the predators feed on for food.
They are usually herbivores and primary consumers in the ecosystem.
Examples of Preys include:
Read more about Feeding relationship here brainly.com/question/9852437
The type of graph that would most appropriately display Sarah's data is a line graph.
<h3>What is a line graph?</h3>
A line graph, sometimes referred to as a line plot or a line chart, is a graph in which individual data points are connected by lines. A line graph shows numerical values over a predetermined period of time.
Line graphs are frequently used in finance to show the historical price movement of an asset or instrument. To monitor changes over both short and long time periods, line graphs are utilized. Line graphs can be used to compare changes for multiple groups over the same time period.
In this case, it should be noted that Sarah wants to compare the speed and the height. Therefore, the line graph and s appropriate.
Learn more about graph on:
brainly.com/question/19040584
#SPJ1
Answer:
Q₂ = 5833.33 J
Explanation:
First we need to find the energy supplied to the heat engine. The formula for the efficiency of the heat engine is given as:
η = W/Q₁
where,
η = efficiency of engine = 30% = 0.3
W = Work done by engine = 2500 J
Q₁ = Heat supplied to the engine = ?
Therefore,
0.3 = 2500 J/Q₁
Q₁ = 2500 J/0.3
Q₁ = 8333.33 J
Now, we find the heat discharged to lower temperature reservoir by using the formula of work:
W = Q₁ - Q₂
Q₂ = Q₁ - W
where,
Q₂ = Heat discharged to the lower temperature reservoir = ?
Therefore,
Q₂ = 8333.33 J - 2500 J
<u>Q₂ = 5833.33 J</u>
