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babymother [125]
3 years ago
5

A triangle drawn on a map has sides that measure 15 cm, 8 cm, and 10 cm. The shortest of the corresponding real-life distances i

s 99 km. Find the longest of the real-life distances.
Mathematics
1 answer:
KIM [24]3 years ago
3 0
The shortest side on the map is 8 cm. This IN real-life distances is 99 km. To find the ratio, we need to change 99 km to cm.
99 \: km \times  \frac{1000 \: m}{1 \: km}  \times  \frac{100 \: cm}{1m}  \\ 99 \: km = 9900000 \: cm
This is a ratio of
8 \times r= 9900000 \\ r =  \frac{9900000}{8}  \\ r = 1237500
Now that we have the ratio, we can find the longest side of the triangle.

The longest side of the triangle is 15 cm.
15 \times 1237500 = 18562500 \: cm
In km, this is
18562500 \: cm \times  \frac{1m}{100cm}  \times  \frac{1km}{1000m}  \\ 18562500 \: cm = 185.625 \: km
The longest side of the real-life triangle is 185.625 km, or 185 5/8 km
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