Question

A triangle drawn on a map has sides that measure 15 cm, 8 cm, and 10 cm. The shortest of the corresponding real-life distances is 99 km. Find the longest of the real-life distances.

Answer 1

The shortest side on the map is 8 cm. This IN real-life distances is 99 km. To find the ratio, we need to change 99 km to cm.
$99 \: km \times \frac{1000 \: m}{1 \: km} \times \frac{100 \: cm}{1m} \\ 99 \: km = 9900000 \: cm$
This is a ratio of
$8 \times r= 9900000 \\ r = \frac{9900000}{8} \\ r = 1237500$
Now that we have the ratio, we can find the longest side of the triangle.

The longest side of the triangle is 15 cm.
$15 \times 1237500 = 18562500 \: cm$
In km, this is
$18562500 \: cm \times \frac{1m}{100cm} \times \frac{1km}{1000m} \\ 18562500 \: cm = 185.625 \: km$
The longest side of the real-life triangle is 185.625 km, or 185 5/8 km