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Over [174]
3 years ago
6

Suppose a computer manufacturer can build circuit boards according to the following process:12 resistors + 20 insulators + 8 mem

ory chips → 4 circuit boards.How many circuit boards could you make using 5 insulators, assuming you have enough of all the other parts?a. 4b.20c.1d.15e.none of the above

Chemistry
1 answer:
melomori [17]3 years ago
6 0

Complete Question:

The complete question is shown on the first uploaded image

Answer:

The answer is option C

Explanation:

From the question we are told that

12 resistors + 20 insulators + 8 memory chips → 4 circuits

Now from this expression we can see that

       20 insulators produces 4 circuit

And we are being as to calculate how many circuit  5 insulators would produce

     S using basic relation we have that

                       20 is to  4

          then      5  is to    ?                             let call ? = x

  applying cross multiplication we have that

                20  ×  x = 4 × 5

  Therefore   x =  (4 ×  5)  ÷   20

                      x   =   1 circuit

We can see from our calculation that 5 insulators would produce one circuit                    

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K = °C + 273 A 4.1 L sample of gas is held at 25 °C. If the gas expands to 6.8 L, what is the final temperature?
gregori [183]

Answer:

221 °C

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 4.1 L

Initial temperature (T₁) = 25 °C

= 25 °C + 273

= 298 K

Final volume (V₂) = 6.8 L

Final temperature (T₂) =?

The final temperature of the gas can be obtained as follow:

V₁ / T₁ = V₂ / T₂

4.1 / 298 = 6.8 / T₂

Cross multiply

4.1 × T₂ = 298 × 6.8

4.1 × T₂ = 2026.4

Divide both side by 4.1

T₂ = 2026.4 / 4.1

T₂ ≈ 494 K

Finally, we shall convert 494 K to celcius temperature. This can be obtained as follow:

°C = K – 273

K = 494

°C = 494 – 273

°C = 221 °C

Thus the final temperature of the gas is 221 °C

6 0
3 years ago
Infer Xenon, a nonreactive gas used in strobe lights, is a poor conductor of heat and electricity. Would you expect xenon to be
lesantik [10]

Mark the lime poor conducter of heat and electricity.

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4 0
2 years ago
Kc = 3.07 x 10-4 at 24°C for 2NOBr(g) ↔ 2NO(g) + Br2(g). If the initial concentration of NOBr = 0.878 M, what is the equilibrium
pav-90 [236]

Answer:

The equilibrium concentration of NO is 0.02124 M.

Explanation:

Given that,

Initial concentration of NOBr = 0.878 M

k_{c}=3.07\times10^{-4}

Temperature = 24°C

We know that,

The balance equation is

2NOBr\Rightarrow 2NO+Br_{2}

Initial concentration is,

0.878\Rightarrow 0+0

Concentration is,

-2x\Rightarrow 2x+x

Equilibrium concentration

0.878-2x\Rightarrow 2x+x

We need to calculate the value of x

Using formula of concentration

k_{c}=\dfrac{[NO][Br_{2}]}{[NOBr]^2}

Put the value into the formula

3.07\times10^{-4}=\dfrac{[2x][x]}{[0.878-2x]^2}

2x^2=3.07\times10^{-4}\times(0.878)^2+3.07\times10^{-4}\times4x^2-2\times2x\times0.878\times3\times10^{-4}

2x^2=0.0002367+0.001228x^2-0.0010536x

2x^2-0.001228x^2+0.0010536x-0.0002367=0

1.998772x^2+0.0010536x-0.0002367=0

x=0, 0.01062

We need to calculate the equilibrium concentration of NO

Using formula of concentration of NO

concentration\ of\ NO=2x

Put the value of x

concentration\ of\ NO=2\times0.01062

concentration\ of\ NO=0.02124

Hence, The equilibrium concentration of NO is 0.02124 M.

7 0
3 years ago
The activation energy for the isomerization ol cyclopropane to propene is 274 kJ/mol. By what factor does the rate of this react
Bond [772]

Answer:

The rate of the reaction increased by a factor of 1012.32

Explanation:

Applying Arrhenius equation

ln(k₂/k₁) = Ea/R(1/T₁ - 1/T₂)

where;

k₂/k₁ is the ratio of the rates which is the factor

Ea is the activation energy = 274 kJ/mol.

T₁ is the initial temperature = 231⁰C = 504 k

T₂ is the final temperature = 293⁰C = 566 k

R is gas constant = 8.314 J/Kmol

Substituting this values into the equation above;

ln(k₂/k₁) = 274000/8.314(1/504 - 1/566)

ln(k₂/k₁) = 32956.4589 (0.00198-0.00177)

ln(k₂/k₁)  = 6.92

k₂/k₁ = exp(6.92)

k₂/k₁ = 1012.32

The rate of the reaction increased by 1012.32

3 0
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