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Ksju [112]
3 years ago
13

Who was the first governor of the Massachusetts Bay Colony?

Chemistry
1 answer:
Svetlanka [38]3 years ago
8 0

Answer: John winthrop

Explanation:

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Having a child will change your financial obligations, and can lead to a career change.
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Yes, that's a true statement?
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3 years ago
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During a titration the following data were collected. A 50.0 mL portion of an HCl solution was titrated with 0.500 M NaOH; 200.
Travka [436]

<u>Answer:</u> The mass of HCl present in 500 mL of acid solution is 36.5 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=50.00mL\\n_2=1\\M_2=0.500M\\V_2=200.mL

Putting values in above equation, we get:

1\times M_1\times 50.00=1\times 0.500\times 200\\\\M_1=\frac{1\times 0.500\times 200}{1\times 50.00}=2M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Molar mass of HCl = 36.5 g/mol

Molarity of solution = 2 M

Volume of solution = 500 mL

Putting values in above equation, we get:

2mol/L=\frac{\text{Mass of solute}\times 1000}{36.5g/mol\times 500}\\\\\text{Mass of solute}=\frac{2\times 36.5\times 500}{1000}=36.5g

Hence, the mass of HCl present in 500 mL of acid solution is 36.5 grams

4 0
2 years ago
Which compound is bonded covalently? A.KF B.MgS C.BeO D.SO2
Masja [62]

Answer:

SO2 is bonded covalently

Explanation:

Atoms that share electrons in a chemical bond have covalent bonds.

6 0
2 years ago
If 1.9 kJ of heat is transferred to 96 g aluminum at 113°C, what would the
erastova [34]

Answer:

T2 = 135.1°C

Explanation:

Given data:

Mass of water = 96 g

Initial temperature = 113°C

Final temperature = ?

Amount of energy transfer = 1.9 Kj (1.9×1000 = 1900 j)

Specific heat capacity of aluminium = 0.897 j/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

Now we will put the values in formula.

Q = m.c. ΔT

1900 j = 96 g × 0.897 j/g.°C × T2 - 113°C

1900 j = 86.112 j/°C × T2 - 113°C

1900 j / 86.112 j/°C = T2 - 113°C

22.1°C + 113°C =  T2

T2 = 135.1°C

4 0
3 years ago
4.1 moles of sodium carbonate to molecules of sodium carbonate.​
docker41 [41]
<h3>Answer:</h3>

2.47 × 10^24 molecules

<h3>Explanation:</h3>

One mole of a compound contains molecules equivalent to the Avogadro's number, 6.022 × 10^23.

That is, 1 mole of a compound =  6.022 × 10^23 molecules

Therefore,

1 mole of Na₂CO₃ = 6.022 × 10^23 molecules

Thus, we can calculate the number of molecules in 4.1 moles of Na₂CO₃

we get,

 = 4.1 moles × 6.022 × 10^23 molecules

 = 2.47 × 10^24 molecules

Hence, 4.1 moles of Na₂CO₃ contains 2.47 × 10^24 molecules

3 0
3 years ago
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