Answer : The work done by the system is, 2.2722 J
Explanation :
The expression used for work done in reversible isothermal expansion will be,
![w=nRT\ln (\frac{V_2}{V_1})](https://tex.z-dn.net/?f=w%3DnRT%5Cln%20%28%5Cfrac%7BV_2%7D%7BV_1%7D%29)
where,
w = work done = ?
n = number of moles of gas = 0.00100 mole
R = gas constant = 8.314 J/mole K
T = temperature of gas = ![25^oC=273+25=298K](https://tex.z-dn.net/?f=25%5EoC%3D273%2B25%3D298K)
= initial volume of gas = 25 mL
= final volume of gas = 75 mL
Now put all the given values in the above formula, we get:
![w=0.00100mole\times 8.314J/moleK\times 298K\times \ln (\frac{75}{25})](https://tex.z-dn.net/?f=w%3D0.00100mole%5Ctimes%208.314J%2FmoleK%5Ctimes%20298K%5Ctimes%20%5Cln%20%28%5Cfrac%7B75%7D%7B25%7D%29)
![w=2.722J](https://tex.z-dn.net/?f=w%3D2.722J)
Therefore, the work done by the system is, 2.2722 J
Answer:
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Explanation:
Explanation:
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