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3 years ago

Give 2 examples of energy transformation that occur when making toast in a toaster oven

Chemistry

1 answer:

Anastasy [175]3 years ago

5 0

When making toast in toast oven, the following energy transformation occur

a) electric energy is converted to heat energy which heat up the filaments of toaster, which helps in roasting of toast.

b)the heat energy is transferred to bread or toast

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Consider 100.0 g samples of two different compounds consisting only of carbon and oxygen. One compound contains 27.2 g of carbon

Pani-rosa [81]

Answer: The ratio of carbon in both the compounds is 1 : 2

Explanation:

Law of multiple proportions states that when two elements combine to form two or more compounds in more than one proportion. The mass of one element that combine with a given mass of the other element are present in the ratios of small whole number. For Example: $Cu_2O\text{ and }CuO$

For Sample 1:

Total mass of sample = 100 g

Mass of carbon = 27.2 g

Mass of oxygen = (100 - 27.7) = 72.8 g

To formulate the formula of the compound, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{27.2g}{12g/mole}=2.26moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{72.8g}{16g/mole}=4.55moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 2.26 moles.

For Carbon = $\frac{2.26}{2.26}=1$

For Oxygen = $\frac{4.55}{2.26}=2.01\approx 2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 2

Hence, the formula for sample 1 is $CO_2$

For Sample 2:

Total mass of sample = 100 g

Mass of carbon = 42.9 g

Mass of oxygen = (100 - 42.9) = 57.1 g

To formulate the formula of the compound, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{42.9g}{12g/mole}=3.57moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{57.1g}{16g/mole}=3.57moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.57 moles.

For Carbon = $\frac{3.57}{3.57}=1$

For Oxygen = $\frac{3.57}{3.57}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 1

Hence, the formula for sample 1 is $CO$

In the given samples, we need to fix the ratio of oxygen atoms.

So, in sample one, the atom ratio of oxygen and carbon is 2 : 1.

Thus, for 1 atom of oxygen, the atoms of carbon required will be = $\frac{1}{2}\times 1=\frac{1}{2}$

Now, taking the ratio of carbon atoms in both the samples, we get:

$C_1:C_2=\frac{1}{2}:1=1:2$

Hence, the ratio of carbon in both the compounds is 1 : 2

8 0

3 years ago

The molecule mass of sodium oxide na2o is

maxonik [38]

it is 61.97894 g/mol

7 0

3 years ago

Read 2 more answers

Why are valence electrons important

koban [17]

Explanation:

The electrons in the outermost shell of an atom are the valence electrons. These electrons are the most loosely held in an atom.

The energy required to remove these electrons are not as great as those of the inner shell electrons.

Atoms of some elements show no tendency to combine with other atoms because they have completely filled outer energy levels.
Their outermost shell, valence shell and the electron numbers are complete for them. These are the noble gases.
other atoms share or exchange their valence electrons in order to have a stable configuration.
The valence electrons are involve in inter-atomic bond formation and interactions
Also the distribution of these electrons determines inter-molecular interactions between molecules.

Learn more:

valence electrons in metalloids brainly.com/question/3023499

#learnwithBrainly

4 0

3 years ago

Read 2 more answers

If you have 6 moles of reactant A and excess of B and C, how much product E would be formed

pychu [463]

B and C are in excess so amount of E will be determined by A.

Amount of product is determined by limiting reagents - Always.

Hence 6 moles of E will be formed.

Hope this helps!

3 0

3 years ago

What is the pOH of a solution that has an H+=7.7x10^-7 M

pentagon [3]

Answer:

Explanation:

Step 1

The question is based on the concept of PH and pOH calculations.

pH is defined as negative logarithmic of hydronium Ion concentration.

while pOH is defined as negative logarithmic of hydroxide ion concentration of the solution.

Step 2

[H+] = 7.7*10-7 M

pH = -log[H+]

= -log ( 7.7*10-7 )

= 6.12

Step 3

pOH = 14 - pH

= 14 - 6.11

= 7.89

4 0

3 years ago