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Helen [10]
3 years ago
12

For each trial, compute the mol of titrant; (molarity x L) and keep the number of significant figures to 4.

Chemistry
2 answers:
zimovet [89]3 years ago
5 0

Answer:

0.0025 mol

0.0025 mol

0.0024 mol

Explanation:

just did lab on edge

hope this helps!!!

MrMuchimi3 years ago
3 0

Answer:

Trial     Number of moles

           

  1          0.001249mol

  2         0.001232mol

  3          0.001187 mol

Explanation:

To calculate the <em>number of moles of tritant</em> you need its<em> molarity</em>.

Since the<em> molarity</em> is not reported, I will use 0.1000M (four significant figures), which is used in other similar problems.

<em>Molarity</em> is the concentration of the solution in number of moles of solute per liter of solution.

In this case the solute is <em>NaOH</em>.

The formula is:

          Molarity=\dfrac{\text{Number of moles of solute}}{\text{Volume of solution in liters}}

Solve for the <em>number of moles:</em>

          \text{Number of moles}=Molarity\times Volume\text{ }in\text{ }liters

Then, using the molarity of 0.1000M and the volumes for each trial you can calculate the number of moles of tritant.

Trial    mL           liters          Number of moles

           

1          12.49       0.01249        0.01249liters × 0.1000M = 0.001249mol

2         12.32      0.01232         0.01232liters × 0.1000M = 0.001232mol

3          11.87       0.01187         0.01187liters × 0.1000M = 0.001187 mol

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3 years ago
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If the pH is 10, what is the concentration of hydroxide ion?
AleksandrR [38]

Answer : The correct option is, 10^{-4}M

Explanation : Given,

pH = 10

First we have to calculate the pOH.

pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-10=4

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pOH=-\log [OH^-]

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[OH^-]=1.0\times 10^{-4}M

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7 0
3 years ago
When optically active (S)-2-methylcyclopentanone is treated with aqueous base, the compound loses its optical activity. Explain
Sunny_sXe [5.5K]

Answer:

See explanation below

Explanation:

In this case, we need to see which is the structure of this compound. Now, racemization occurs basically because we are in an aqueous basic medium, and the ketone can reacts again with water in the medium to form the starting reagent.

First, the base will take out the Alpha hydrogen from the ketone, then, the negative charge goes down and opens up the carbonile group, forming a double bond in there. Later, with the water of the medium, it reacts and substract a proton, and then, with keto enolic equilibrium, forms again the ketone, but this ketone is different from the start, it will be the  R isomer which is not optically active.

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6.11% w/v of Cu2+ implies that 6.11 g of Cu2+ is present in 100 ml of the solution

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The mass of CuCl2 required = 0.2404 moles * 134.452 g/mole = 32.32 grams

6 0
3 years ago
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