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3 years ago

Which of the following pairs of reactants will react together to produce water (H2O) as one of the products?

2 answers:

7 0

1) NaNO3 and H2O - no reaction , it is dissolution
2) no hydrogen to make water
3) Fe(OH)3 (base) and H2SO4(acid))
base +acid ----> salt +water
4) Li2O and Ba(OH)2
basic oxide and base ----> no reaction

so Answer number 3)
 2Fe(OH)3 +3 H2SO4 ------> Fe2(SO4)3 + 6H2O

AlexFokin [52]3 years ago

3 0

Answer: The correct pair is, $Fe(OH)_3\text{ and }H_2SO_4$

Explanation :

(1) $NaNO_3\text{ and }H_2O$

The balanced chemical reaction will be,

$NaNO_3+H_2O\rightarrow NaOH+HNO_3$

(2) $Mg_3(PO_4)_2\text{ and }Al_2O_3$

The balanced chemical reaction will be,

$Mg_3(PO_4)_2+Al_2O_3\rightarrow 2AlPO_4+3MgO$

(3) $Fe(OH)_3\text{ and }H_2SO_4$

The balanced chemical reaction will be,

$2Fe(OH)_3+3H_2SO_4\rightarrow Fe_2(SO_4)_3+6H_2O$

(4) $Li_2O\text{ and }Ba(OH)_2$

The balanced chemical reaction will be,

$Li_2O+Ba(OH)_2\rightarrow 2LiOH+BaO$

Hence, the pairs of reactants react together to produce water as one of the product will be, $Fe(OH)_3\text{ and }H_2SO_4$

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A tank at is filled with of sulfur tetrafluoride gas and of sulfur hexafluoride gas. You can assume both gases behave as ideal g

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The question is incomplete, the complete question is:

A 7.00 L tank at $21.4^oC$ is filled with 5.43 g of sulfur hexafluoride gas and 14.2 g of sulfur tetrafluoride gas. You can assume both gases behave as ideal gases under these conditions. Calculate the mole fraction and partial pressure of each gas. Round each of your answers to significant digits.

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Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

For sulfur hexafluoride:

Given mass of sulfur hexafluoride = 5.43 g

Molar mass of sulfur hexafluoride = 146.06 g/mol

Putting values in equation 1, we get:

$\text{Moles of sulfur hexafluoride}=\frac{5.43g}{146.06g/mol}=0.0372mol$

For sulfur tetrafluoride:

Given mass of sulfur tetrafluoride = 14.2 g

Molar mass of sulfur tetrafluoride = 108.07 g/mol

Putting values in equation 1, we get:

$\text{Moles of sulfur tetrafluoride }=\frac{14.2g}{108.07g/mol}=0.1314mol$

Total moles of gas in the tank = [0.0372+ 0.1314] mol = 0.1686 mol

Mole fraction is defined as the moles of a component present in the total moles of a solution. It is given by the equation:

$\chi_A=\frac{n_A}{n_A+n_B}$ .....(2)

where n is the number of moles

Putting values in equation 2, we get:

$\chi_{SF_6}=\frac{0.0372}{0.1686}=0.221$

$\chi_{SF_4}=\frac{0.1314}{0.1686}=0.779$

Hence, the mole fraction of sulfur hexafluoride is 0.221 and that of sulfur tetrafluoride is 0.779

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When hydrogen gas reacts with oxygen gas under certain conditions to produce liquid water, 572.0 kJ of heat energy is released.

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Answer : This reaction is an exothermic reaction.

Explanation :

Endothermic reaction : It is defined as the chemical reaction in which the energy is absorbed from the surrounding.

In the endothermic reaction, the energy of reactant are less than the energy of product.

Exothermic reaction : It is defined as the chemical reaction in which the energy is released into the surrounding.

In the exothermic reaction, the energy of reactant are more than the energy of product.

Enthalpy of reaction : It is the difference between the energy of product and the reactant. It is represented as $\Delta H$ .

The balanced chemical reaction will be:

$H_2(g)+O_2(g)\rightarrow H_2O(l)+572.0kJ$

From the reaction we conclude that the heat energy is released during the reaction that means this reaction is an exothermic reaction.

Hence, the reaction is an exothermic reaction.

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