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anyanavicka [17]
2 years ago
8

12 moles of Cu is how many grams of Cu?

Chemistry
1 answer:
exis [7]2 years ago
3 0

Answer:

762.60 g

Explanation:

In order to convert from moles of a substance into grams, we need to multiply the number of moles by the substance's molar mass:

  • Moles * Molar Mass = Grams

With the above information in mind, we can <em>use the data given by the problem</em> and <u>calculate how many grams are there in 12 moles of Cu</u>:

  • 12 mol * 63.55 g/mol = 762.60 g
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At their centers, all the jovian planets have cores made of:
Paul [167]

Answer:

The core of Jupiter and Saturn is made up of rock,metal and hydrogen compounds, while the core of Uranus and Neptune is made up of rock,metals,water, methane, and ammonia.

Explanation:

The Jovian planets include, Jupiter, Saturn, Uranus, and Neptune. These planets when compared to terrestrial planets are small, with dense cores and surrounded by layers of gas.

5 0
3 years ago
Only _____ live part of their lives like fish and the rest of their lives as land animals.
dedylja [7]

Answer:

amphibians

Explanation:

because frogs have to stay in water while tadpole then they come to land

6 0
2 years ago
Read 2 more answers
Acetylene gas, C2H2, can be produced by the reaction of calcium carbide and water. CaC2(s) + 2H2O(l) --&gt; C2H2(g) + Ca(OH)2(aq
nekit [7.7K]

Answer:

1.0 L

Explanation:

Given that:-

Mass of CaC_2 = 2.54\ g

Molar mass of CaC_2 = 64.099 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{2.54\ g}{64.099\ g/mol}

Moles_{CaC_2}= 0.0396\ mol

According to the given reaction:-

CaC_2_{(s)} + 2H_2O_{(l)}\rightarrow C_2H_2_{(g)} + Ca(OH)_2_{(aq)}

1 mole of CaC_2 on reaction forms 1 mole of C_2H_2

0.0396 mole of CaC_2 on reaction forms 0.0396 mole of C_2H_2

Moles of C_2H_2 = 0.0396 moles

Considering ideal gas equation as:-

PV=nRT

where,

P = pressure of the gas = 742 mmHg  

V = Volume of the gas = ?

T = Temperature of the gas = 26^oC=[26+273]K=299K

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

n = number of moles = 0.0396 moles

Putting values in above equation, we get:

742mmHg\times V=0.0396 mole\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 299K\\\\V=\frac{0.0396\times 62.3637\times 299}{742}\ L=1.0\ L

<u>1.0 L of acetylene  can be produced from 2.54 g CaC_2.</u>

4 0
3 years ago
Use the expression we obtained in class to write the molar absorption coefficient of a particular transition in terms of the tra
Anna007 [38]

Answer:

Initially the function is symmetric with respect to the axis of the one dimensional box. In the final state it is also symmetrical, however you can envision a snapshot of the system as the light field is interacting with the wave-function wherein a node begins to develop as is shown in the middle and the wave function is evolving from the initial to final state. Now consider that the electron density during process is the square of the wave function:

Electron density during transition

As can be seen in the initial and final states the electron density is symmetrically distributed with respect to the axis of the box. However with the field on, the electron density is not symmetrically distributed and a transitory dipole moment can be present. To relate back to real molecules think of each of those orbitals as a linear combination of atomic orbitals. One important factor is the symmetry. But there may be one other factor that will be just as important as symmetry. If you treat orbital 1 as a linear combination over n orbitals and orbital 2 as a linear combinations of orbitals as well, there will be a spatial over lap between the orbital in the ground state and the orbital in the excited state. If there is no spatial overlap between the ground state and excited state orbitals there will be no transition dipole moment. However, if the electrons are in the same place spatially, a large transition dipole moment will result.

Explanation:

4 0
2 years ago
Using the periodic table in your textbook, calculate the molar mass of paraffin (C46H92O2).
ArbitrLikvidat [17]

Answer:

677.39 g/mol

Explanation:

Step 1: Find molar masses of elements

Carbon (C) - 12.01 g/mol

Hydrogen (H) - 1.01 g/mol

Oxygen (O) - 16.00 g/mol

Step 2: Multiply the amount present

12.01 g/mol · 46 = 552.46 g/mol

1.01 g/mol · 92 = 92.92 g/mol

16.00 g/mol · 2 = 32.00 g/mol

Step 3: Add up all the molar masses to find compound molar mass

552.46 g/mol + 92.92 g/mol + 32.00 g/mol = 677.39 g/mol

3 0
3 years ago
Read 2 more answers
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