Yes,covalent bonds do dissolve in methanol
Answer:d
Explanation:I’m not 100% sure how to explain it but I’m almost for sure it’s d.
I believe that it is petroleum ether.
Answer:
2,4,4-trimethyl-2-pentene yields mixture of
and 
Explanation:
In ozonolysis (hydrolysis step involve a reducing agent such as Zn,
etc.), a pi bond is broken to form ketone/aldehyde.
Ketone is formed from di-substituted side of double bond and aldehyde is formed from mono-substituted side of double bond.
Ozoznolysis involves two consecutive steps : (1) formation of ozonide, (2) hydrolysis of ozonide.
Hydrolysis can be done with/without using reducing agent. Carboxylic acid/carbon dioxide/ketone is produced when hydrolysis is done without using reducing agent.
Here, 2,4,4-trimethyl-2-pentene yields mixture of
and 
Reaction steps are shown below.
Tabulations of chemical elements differing in their organization from the traditional seen periodic system