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3 years ago

12 moles of Cu is how many grams of Cu?

Chemistry

1 answer:

exis [7]3 years ago

3 0

Answer:

762.60 g

Explanation:

In order to convert from moles of a substance into grams, we need to multiply the number of moles by the substance's molar mass:

Moles * Molar Mass = Grams

With the above information in mind, we can use the data given by the problem and calculate how many grams are there in 12 moles of Cu:

12 mol * 63.55 g/mol = 762.60 g

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According to Newton’s second law of motion, when an object is acted on by an unbalanced force, how will that object respond? It

otez555 [7]

Answer:

C) It will accelerate.

Explanation:

According to Newton’s second law of motion, when an object is acted on by an unbalanced force, it will accelerate.

An unbalanced force will change the speed or direction (or both) of an object. A change in speed and/or direction is acceleration.

A) is wrong. The object will stop moving only if there is a balanced force in the opposite direction.

B) is wrong. The object will decrease speed only if the unbalanced force has a component opposite to the direction of motion.

d) is wrong. The object will increase speed only if the unbalanced force has a component in the direction of motion.

7 0

3 years ago

Five million gallons per day (MGD) of wastewater, with a concentration of 10.0 mg/L of a conservative pollutant, is released int

hjlf

Answer:

a) The concentration in ppm (mg/L) is 5.3 downstream the release point.

b) Per day pass 137.6 pounds of pollutant.

Explanation:

The first step is to convert Million Gallons per Day (MGD) to Liters per day (L/d). In that sense, it is possible to calculate with data given previously in the problem.

Million Gallons per day $1 MGD = 3785411.8 litre/day = 3785411.8 L/d$

$F_1 = 5 MGD (\frac{3785411.8 L/d}{1MGD} ) = 18927059 L/d\\F_2 =10 MGD (\frac{3785411.8 L/d}{1MGD} )= 37854118 L/d$

We have one flow of wastewater released into a stream.

First flow is F1 =5 MGD with a concentration of C1 =10.0 mg/L.

Second flow is F2 =10 MGD with a concentration of C2 =3.0 mg/L.

After both of them are mixed, the final concentration will be between 3.0 and 10.0 mg/L. To calculate the final concentration, we can calculate the mass of pollutant in total, adding first and Second flow pollutant, and dividing in total flow. Total flow is the sum of first and second flow. It is shown in the following expression:

$C_f = \frac{F1*C1 +F2*C2}{F1 +F2}$

Replacing every value in L/d and mg/L

$C_f = \frac{18927059 L/d*10.0 mg/L +37854118 L/d*10.0 mg/L}{18927059 L/d +37854118 L/d}\\C_f = \frac{302832944 mg/d}{56781177 L/d} \\C_f = 5.3 mg/L$

a) So, the concentration just downstream of the release point will be 5.3 mg/L it means 5.3 ppm.

Finally, we have to calculate the pounds of substance per day (Mp).

We have the total flow F3 = F1 + F2 and the final concentration $C_f$ . It is required to calculate per day, let's take a time of t = 1 day.

$F3 = F2 +F1 = 56781177 L/d \\M_p = F3 * t * C_f\\M_p = 56781177 \frac{L}{d} * 1 d * 5.3 \frac{mg}{L}\\M_p = 302832944 mg$

After that, mg are converted to pounds.

$M_p = 302832944 mg (\frac{1g}{1000 mg} ) (\frac{1Kg}{1000 g} ) (\frac{2.2 lb}{1 Kg} )\\M_p = 137.6 lb$

b) A total of 137.6 pounds pass a given spot downstream per day.

4 0

4 years ago

What is the hardest mineral listed here? A. quartz B. calcite C. gypsum D. corundum

a_sh-v [17]

The answer would be D. The only minerals harder than corundum is diamond.

3 0

4 years ago

Read 2 more answers

How many grams of NaOH needed to completely neutralize 3L of 1.75M HCL

Sedaia [141]

Answer:

209.98 g of NaOH

Explanation:

We are given;

Volume of HCl as 3 L
Molarity of HCl as 1.75 M

We are required to calculate the mass of NaOH required to completely neutralize the acid given.

First, we write a balanced equation for the reaction between NaOH and HCl

That is;

NaOH + HCl → NaCl + H₂O

Second, we determine the number of moles of HCl

Number of moles = Molarity × Volume

= 1.75 M × 3 L

= 5.25 moles

Third, we use the mole ratio to determine the moles of NaOH

From the reaction,

1 mole of NaOH reacts with 1 mole of HCl

Therefore;

Moles of NaOH = Moles of HCl

= 5.25 moles

Fourth, we determine the mass of NaOH

Molar mass of NaOH = 39.997 g/mol

Mass of NaOH = 5.25 moles × 39.997 g/mol

= 209.98 g

Thus, 209.98 g of NaOH will completely neutralize 3L of 1.74 M HCl

6 0

3 years ago

CO + - 02 CO2 Balance the equation

poizon [28]

Answer:

2co+o2=2co2

Explanation:

co+o2=co2

here is one carbon monoxide and two oxygen react with it and forms carbon dioxide..

2co+o2=2co2

hey mate hope it's help you.. please mark it as a brain.... answer

5 0

3 years ago