All categories

3 years ago

temperature usually increase when water condenses which behavior of water is most directly responsible for this phenomenon?

Chemistry

1 answer:

aniked [119]3 years ago

3 0

Answer:

Temperature usually increases when water condenses. What behavior of water is most directly responsible for this phenomenon? The release of heat by the formation of hydrogen bonds. Hydrogen bonds stabilize and keep the of ice farther apart than the water molecules of liquid water.

You might be interested in

A balloon originally had a volume of 4.39 L at 44C and a pressure of 729 torr to what temperature must the balloon be cooled

VMariaS [17]

The new temperature : 11.56 °C

<h3>Further explanation </h3>

Boyle's law and Gay Lussac's law

$\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}$

P1 = initial gas pressure (N/m² or Pa)

V1 = initial gas volume (m³)

P2 = final gas pressure

V2 = final gas volume

T1 = initial gas temperature (K)

T2 = final gas temperature

V₁=4.39 L

T₁=44+273=317 K

P₁ = 729 torr = 0,959211 atm

V₂=3.78 L

P₂= 1 atm

$\tt \dfrac{0.959211\times 4.39}{317}=\dfrac{1\times 3.78}{T_2}\\\\T_2=\dfrac{1\times 3.78\times 317}{0.959211\times 4.39}\\\\T_2=284.559~K=11.56~C$

3 0

3 years ago

The half-life of cesium-137 is 30 years. Suppose we have a 200-mg sample. (a) Find the mass that remains after t years.

scZoUnD [109]

Given:

Half life(t^ 1/2) :30 years

A0( initial mass of the substance): 200 mg.

Now we know that

A= A0/ [2 ^ (t/√t)]

Where A is the mass that remains after t years.

A0 is the initial mass

t is the time

t^1/2 is the half life

Substituting the given values in the above equation we get

A= [200/ 2^(t/30) ] mg

Thus the mass remaining after t years is [200/ 2^(t/30) ] mg

5 0

4 years ago

If a liquid has a Ph of 3 what is it

kvasek [131]

Lower than 7 is acid greater than 7 is a base

6 0

4 years ago

What did you include in your response?<br>check all that apply

erma4kov [3.2K]

Answer: i don't know

Explanation:

u gave no information on what you're asking

6 0

3 years ago

calcualte pressure at STP in 10.0 L vessel after reaction of 1.0 L hydrochloride acid (concentration 35% and density 1.28 g/cub.

sattari [20]

Answer:

The pressure in the vessel is 13,3 atm.

Explanation:

The reaction that occurs in vessel (where limestone is 96% of CaCO₃) is:

2 HCl (aq)+ CaCO₃ (s) → CaCl₂(aq)+ H₂O(l)+ CO₂(g)

The increase in the pressure of the vessel after the reaction is by formation of a gas (CO₂). So we have to find the produced moles of this gas and apply the gas ideal law to find the pressure.

We have to find the limit reactant, to do so, we have to calculate the moles of each reactant in the reaction, the one that have the less moles will be the limit reactant:

HCl:

1,0L × (35/100) × (1000 cm³/1L) × (1,28 g/ 1cm³) × (1mol HCl/ 36,46 g) ÷ 2mol

(Concentration) (L to cm³) (cm³ to g) (g to mol) (moles of reaction)

moles of HCl= 6,14 mol

CaCo₃:

1,0 kg × (96/100) × (1000 g/1kg) × (1 mol/100,09g)

(Limestone) (CaCo₃ in limestone) (kg to g) (g to mol)

moles of CaCo₃= 9,59 mol

So, <em>reactant limit is HCl</em>

This reaction have a yield of 97%. So, the CO₂ moles are:

6,14 mol × 97÷ = 5,96 mol CO₂

The ideal gas formula to obtain pressure is:

P = nRT/V

Where: n = 5,96mol; R= 0,082 atm×L/mol×K; T = 273,15 (until STP conditions) and V= 10,0 L

Replacing this values in the equation the pressure is

P = 13,3 atm

I hope it helps!

7 0

3 years ago