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True [87]
3 years ago
15

List three aids with example that are useful for people who are optically impaired​

Chemistry
1 answer:
fomenos3 years ago
8 0
Magnifying Glasses, Telescopes and Glasses.
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The process in which rock fragments freeze to the bottom of a glacier and then are carried away when the glacier moves is called
guapka [62]
Im pretty sure its called plucking
3 0
3 years ago
Read 2 more answers
Which statement explains why catalysts are important for living
Marina86 [1]

Answer:

Catalysts allow chemical reactions to occur at temperatures at which the organism lives.

Explanation:

Catalysts are molecules that speeden the rate of chemical reaction by lowering the activation energy of the reaction. In a living system, the catalyst are ENZYMES, which help to hasten up many biochemical reactions.

Another function of catalyst in living systems is that it allows chemical reactions to occur at temperatures at which the organism lives.

8 0
3 years ago
Should the density of a metal depend on its volume?
jekas [21]

Answer:

Density is the ratio of the mass of an object to its volume. Density is an intensive property, meaning that it does not depend on the amount of material present in the sample. ... Since a cubic centimeter is equal to a milliliter, density units can also be expressed as g/mL.

Explanation:

6 0
3 years ago
What is the ph of a solution of 0.550 m k2hpo4, potassium hydrogen phosphate?
Solnce55 [7]
We assume that we have Ka= 4.2x10^-13 (missing in the question)
and when we have this equation:
H2PO4 (-) → H+  + HPO4-
and form the Ka equation we can get [H+]:
Ka= [H+] [HPO4-] / [H2PO4] and we have Ka= 4.2x10^-13 & [H2PO4-] = 0.55m
by substitution:
4.2x10^-13 = (z)(z)/ 0.55
z^2 = 2.31x 10^-13
z= 4.81x10^-7
∴[H+] = 4.81x10^-7
when PH equation is:

PH= -㏒[H+]
     = -㏒(4.81x10^-7) = 6.32

3 0
3 years ago
A sample of hydrogen occupies a volume of 351 mL at a temperature of 20 degrees Celsius. What is the new volume if the temperatu
xeze [42]
Volume of Hydrogen V1 = 351mL 
Temperature T1 = 20 = 20 + 273 = 293 K 
Temperature T2 = 38 = 38 + 273 = 311 K 
We have V1 x T2 = V2 x T1 
So V2 = (V1 x T2) / T1 = (351 x 311) / 293 = 372.56 
Volume at 38 C = 373 ml
6 0
3 years ago
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