Q12. How much force is applied on the body when 150 joule of work
1 answer:
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Answer:
14m/s
Explanation:
Given parameters:
Radius of the curve = 50m
Centripetal acceleration = 3.92m/s²
Unknown:
Speed needed to keep the car on the curve = ?
Solution:
The centripetal acceleration is the inwardly directly acceleration needed to keep a body along a curved path.
It is given as;
a =
a is the centripetal acceleration
v is the speed
r is the radius
Now insert the parameters and find v;
v² = ar
v² = 3.92 x 50 = 196
v = √196 = 14m/s
Answer:
(a). The spring compressed is .
(b). The acceleration is 1.5 g.
Explanation:
Given that,
Acceleration = a
mass = m
spring constant = k
(a). We need to calculate the spring compressed
Using balance equation
....(I)
The spring compressed is .
(b). If the compression is 2.5 times larger than it is when the mass sits in a still elevator,
The compression is given by
Here, acceleration is zero
So,
We need to calculate the acceleration
Put the value of x in equation (I)
Hence, (a). The spring compressed is .
(b). The acceleration is 1.5 g.