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NeX [460]
3 years ago
6

Q12. How much force is applied on the body when 150 joule of work

Physics
1 answer:
ra1l [238]3 years ago
4 0

Force = Work/distance

Force = 150/10

          =  15 Newtons

Force = 15 Newtons

Therefore, 15 newtons of force is applied to the body when 150 joules of work

is done in displacing the body through a distance of 10m in the  direction of the force.

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A reaction between an acid and a base is called a(n) ________________ reaction. A) hydro B) ionization C) neutralization D) redo
mario62 [17]

Answer:

It would be a neutralization reaction if i do believe so

Explanation:

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6 0
3 years ago
A 2 kilogram object falls a distance of 5 meters. How much potential energy does this object have before it falls? How much work
Y_Kistochka [10]

1) Potential energy before the fall: 98 J

The gravitational potential energy of an object is given by:

U=mgh

where m is the mass of the object, g is the gravitational acceleration and h the heigth of the object above the ground.

In this problem, m = 2 kg, g = 9.8 m/s^2 and h = 5 m: substituting into the equation, we find

U=(2 kg)(9.8 m/s^2)(5 m)=98 J


2) Work done by gravity: 98 J

The work done by a force is given by:

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and the displacement

In this problem:

F=mg=(2 kg)(9.8 m/s^2)=19.6 N

d = 5 m

\theta=0^{\circ}

Therefore,

W=(19.6 N)(5 m)(cos 0^{\circ})=98 J

5 0
3 years ago
What is the easiest way to increase the magnetic force acting on the rotor in an induction motor?
Schach [20]

Answer:

Explanation:

Magnets are of two major forms namely the permanent magnet and the temporary magnets. Temporary magnets magnetizes and demagnetize easily while permanent magnets does not magnetizes and demagnetize easily.

This permanents magnets are applicable in loudspeakers, generators, induction motor etc.

To increase the

The following will tend to increase the magnetic force acting on the rotor in an induction motor.

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6 0
3 years ago
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sertanlavr [38]

Answer:

P = 27.8 Watt

Explanation:

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so we can say that

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so we need to find the metabolic power which is given as

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so here we have

F = mg sin\theta

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now we have

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P = 27.8 Watt

3 0
3 years ago
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