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Blizzard [7]
2 years ago
8

If the mass of the cement is 15 000 kg, calculate the density of this cement sample in kgm-3

Physics
1 answer:
MrRa [10]2 years ago
5 0

Explanation:

Hi there!

Mass of the container (m) = 15000 kg

Also from the figure;

Volume of the container (V) = l*b*h

{ From figure length = 2m , breadth = 1.1m, height = 2.5m}

So,

V = (2*1.1*2.5) m³

= 5.5m³

Then;

Density (d) = m/v

= 15000/5.5

= 2727.27 kgm³

Therefore, the density is 2727.27 kgm³.

Hope it helps!

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4 0
1 year ago
A ball is thrown at an angle of 38° to the horizontal. What happens to the
finlep [7]

Answer:

Vy = V0 sin 38       where Vy is the initial vertical velocity

The ball will accelerate downwards (until it lands)

Note the signs involved   if Vy is positive then g must be negative

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t (upwards) = (0 - Vy) / -g      = Vy / g      final velocity = 0

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8 0
2 years ago
If a 60-watt bulb is used to light a room, how much current is flowing through the bulb given that the voltage is 120 volts?
Pavel [41]
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3 0
2 years ago
Newtons first law 1 to 5. <br>What is each of the net force for all of the 5 questions? ​
erica [24]

Answer:

1. 65 N.

2. 160 N.

3. 0 N.

4. 210 N.

5. 90 N.

Explanation:

1. Determination of the net force.

Force applied to the right (Fᵣ) = 80 N

Force applied to the left (Fₗ) = 145 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 145 – 80

Fₙ = 65 N

Thus, the net force is 65 N

2. Determination of the net force.

Force 1 applied to the left (F₁) = 35 N

Force 2 applied to the left (F₂) = 125 N

Net force (Fₙ) =?

Fₙ = F₁ + F₂

Fₙ = 35 + 125

Fₙ = 160 N

Thus, the net force is 160 N.

3. Determination of the net force.

Force applied to the right (Fᵣ) = 75 N

Force applied to the left (Fₗ) = 75 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 75 – 75

Fₙ = 0

Thus, the net force is 0 N

4. Determination of the net force.

Force 1 applied to the right (F₁) = 150 N

Force 2 applied to the right (F₂) = 60 N

Net force (Fₙ) =?

Fₙ = F₁ + F₂

Fₙ = 150 + 60

Fₙ = 210 N

Thus, the net force is 210 N.

5. Determination of the net force.

Force applied to the right (Fᵣ) = 115 N

Force applied to the left (Fₗ) = 25 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 115 – 25

Fₙ = 90 N

Thus, the net force is 90 N

8 0
3 years ago
SOMEONE HELP ME PLSS​
lara31 [8.8K]
1. 2500/60 joules/sec
2. 2,500Nm
7 0
3 years ago
Read 2 more answers
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