1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
elena-14-01-66 [18.8K]
3 years ago
7

In an insulated container, 0.50 kg of water at 80°C is mixed with 0.050 kg of ice at −5.0°C. After a while, all the ice melts, l

eaving only the water. Find the final temperature T_f of the water. The freezing point of water is 0°C.
Physics
2 answers:
Phoenix [80]3 years ago
6 0

Explanation:

When ice tends to absorb heat energy then it will change into liquid state. Now,  change in the temperature of cold water dT = T_{f} - 0^{o}C = T_{f}

Change in the temperature of original water in the container dT' = 80 -T_{f
}

Latent heat of melting of ice L = 80 cal/g

Specific heat of water C = 1 cal/g C

Heat absorbed by ice to melt = mass(m_{i}) x latent heat(L)

Heat absorbed by water = mass(m_{w}) x specific heat(C) x change in temperature (dT')

m_{i} = 0.050 kg = 50 g and m_{w} = 0.50 kg = 500 g

Now, heat lost by water is as follows.

heat lost by hot water( at 80^{o}C)  = heat absorbed by the ice + heat absorbed by cold water

         m_{i} \times L + m_{i} \times C dT = m_{w} \times C dT'

            50 \times 80 + 50 \times 1 \times (T_{f}) = 500 \times 1 \times (80 - T_{f})

So, we will cancel out 50 from each term given above. Hence,

              80 + T_{f} = 800 - 10T_{f}  

               11 T_{f} = 720

               T_{f} = 65.45^{o}C

Thus, we can conclude that final temperature of the water is 65.45^{o}C.

Morgarella [4.7K]3 years ago
5 0

Answer:

T_f=68.808\ ^{\circ}C

Explanation:

Given:

  • mass of water, m_w=0.5\ kg
  • initial temperature of water, T_{wi}=80^{\circ}C
  • mass of ice, m_i=0.05\ kg
  • initial temperature of ice, T_{ii}=-5^{\circ}C
  • Specific heat capacity of water, c_w=4186\ J.kg^{-1}.K^{-1}
  • Specific heat capacity of ice, c_i=2100\ J.kg^{-1}.K^{-1}
  • Latent heat of fusion of ice, L=335000\ J.kg^{-1}

<u>Now according to the given that the whole ice melts:</u>

using energy conservation with heat,

m_i.c_i.(T_f-T_i)+m_i.L+m_w.c_w.(T_f-T_i)=0

m_i.c_i.(T_f-T_i)+m_i.L=m_w.c_w.(T_i-T_f)

0.05\times 2100\times (T_f-(-5))+0.05\times 335000=0.5\times 4186\times (80-T_f)

T_f=68.808\ ^{\circ}C

You might be interested in
Explain why water boiling in a container stops<br>boiling momentarily when the lid is removed​
Dmitriy789 [7]

Answer:

It's because it tips over the threshold from nucleate boiling, which we can see, to convection boiling, which we can't. ... Even if the steam stayed in the pot, it would still stop boiling when you removed the heat. The steam and water in a liquid/vapour mixture are at the same temperature (100ºC).

Explanation:

8 0
4 years ago
Three forces are applied to a solid cylinder of mass 12 kg (see the drawing). The magnitudes of the forces are F1 = 15 N, F2 = 2
Mila [183]

Answer:

The angular acceleration is 11.66 rad/s²

Explanation:

Step 1: Given data

Three forces are applied to a solid cylinder of mass 12 kg

F1 = 15 N

F2 = 24 N

F3 = 19 N

R2 = 0.22m

R3 = 0.10m

Step 2: Find the magnitude of the angular acceleration

I = ½mr² = ½ * 12kg * (0.22m)² = 0.29 kg*m²

torque τ = I*α

τ = F2*R2 - F1*R1 = 24N*0.22m - 19N*0.10m = 3.38 N*m

This means

I = ½mr² = 0.29 kg*m²

τ = I*α  =  3.38 N*m

OR

0.29 kg*m² * α = 3.38 N*m

α = 11.655 rad/s²  ≈11.66 rad/s²

The angular acceleration is 11.66 rad/s²

6 0
4 years ago
Convert 60 km/ hr into m/s
elixir [45]

Answer:

1 KM per minute is the real speed in minutes, turn that into 1000 meters per minute and divided by 60, you get a good number of 16.6666666667 which means you could go 50 meters per 3 seconds

Explanation:

so it would be 16.6666666667 meters per second

4 0
3 years ago
mass is 5 lb attached to a rope wound around a pulley. The radius of the pulley is 3 in. If the mass falls at a constant velocit
suter [353]

Answer:

The power transmitted to the pulley is 0.0455 hp.

Explanation:

Given;

mass attached to the rope, m = 5 lb

radius of the pulley, r = 3 in

constant rate of fall of the mass, v = 5 ft/s

acceleration due to gravity, g = 32.2 ft/s²

1 lbf = 32.2 lb.ft/s²

The power transmitted to the pulley is calculated as;

P = Fv

P = (mg)v

P = 5 \ lb \ \times \ 32.2 \ \frac{ft}{s^2} \ \times \ 5 \ \frac{ft}{s} \ \times \ \frac{1 \ lbf}{32.2 \ lb.ft/s^2}  \ \ = 25 \ \frac{ft.lbf}{s} \\\\

in horse power, the power transmitted is calculated as;

P = \frac{25 \ ft.lbf}{s} \ \times \ \frac{1 \ hp}{550 \ ft.lbf/s}  \ \ = 0.0455 \ hp

Therefore, the power transmitted to the pulley is 0.0455 hp.

3 0
3 years ago
1) Consider a source particle of charge qS=9 C located at (−9,5) [distances in meters]. Find the electric field vector at the ta
xeze [42]

Answer:

1)  E = 2.25 i^+ 0.809j^)  10⁹ N / C , 2)   E = 2.39 10⁹ N / C , 3)    θ = 19.8º , 4)   F = 19.12 10⁹ N , 5)  E = (1.32 i^+ 3.56 j^) 109 N/C

Explanation:

1) The equation for the electric field is

       E = k q / r²

Where K is the Coulomb constant that is worth 8.99 10⁹ N m² /C², q is the load and r is the distance of the load to the test point

Since the electric field is a vector magnitude, we can find its component

X axis

     Ex = k q / x²

where the distance on the axis is

      x = √ (X₂-x₁)²

      x = √ (-15 + 9)² = 6 m

      Eₓ = 8.99 10⁹ 9/6²

      Eₓ = 2.25 10⁹ N /C

Y Axis

     y = √ (y₂-y₁)² = √ (15-5)² = 10 m

     E_{y} = 8.99 10⁹ 9/10²

      E_{y}  = 0.809 10⁹ N / C

     

     E = Eₓ i^+   E_{y}  j^

     E = 2.25 i^+ 0.809j^)  10⁹ N / C

2) the magnitude can be found using the Pythagorean triangle

        E = √ (Eₓ² +  E_{y}²)

        E = √ (2.25² + 0.809²) 10⁹

        E = 2.39 10⁹ N / C

3) to find the angle let's use trigonometry

       tan θ = E_{y} / Eₓ

       θ = tan⁻¹ E_{y} / Eₓ

       θ = tan⁻¹ (0.809 / 2.25)

       θ = 19.8º

Regarding the positive side of the x axis

4) a charge  q2 = 8C is placed, let's calculate the force

      F = q E

      F = 8 2.39 10⁹

      F = 19.12 10⁹ N

5) The total electric field at the origin, let's look for its components

     q₁ = 9C

     r₁ = -9 i ^ + 5 j ^

     q₂ = 8 C

     r₂ = -15 i ^ + 15 j ^

X axis

     Eₓ = E₁ₓ + E₂ₓ

     Eₓ = k q₁ / Dx₁² + k q₂ / Dx₂²

     Eₓ = 8.99 10⁹ (9 / (9-0)² + 8 / (15-0)²)

     Eₓ = 1.32 109 N / A

Y Axis

    E_{y} =  E_{1y} + E_{2y}

      E_{y} = k q₁ / Δy₁² + k q₂ / Δy₂²

      E_{y} = 8.99 109 (9/5² + 8/15²)

      E_{y} = 3.56 109 N / A

     E = (1.32 i^+ 3.56 j^) 109 N/C

7 0
4 years ago
Other questions:
  • Does air resistance increase or decrease the acceleration of a falling object
    11·1 answer
  • If a magnet is broken into two pieces, what happens to the magnetic poles? One piece will have a north pole, while the other pie
    15·2 answers
  • What happens to the wavelength as the frequency of a whale noise changes from 200hz to 300hz
    14·1 answer
  • The best kind of bridge...using popsicle sticks? What bridge holds the most weight...how do youmake a popsicle stick that won't
    8·1 answer
  • For nitrogen feel like with its temperature must be within 12.78 Fahrenheit of -333.22 Fahrenheit which equation can be used to
    7·2 answers
  • A racing car increases its speed from 10 m/s to 50 m/s over a distance of 60 m.
    11·1 answer
  • Which color is more energetic orange or blue ? why?
    9·1 answer
  • Quick question plz.........If force acting on a body of mass 40kg is doubled. By how much will be the acceleration change?
    5·2 answers
  • What happens to the gravitational force between two objects if:
    14·1 answer
  • Which of these forms of radiation passes most easily through the disk of the milky way?.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!