How many atoms of fluoride are there in one molecule of nitrogen trifluoride?
2 answers:
Answer : The number of atoms of fluoride present in one molecule of are, 3.
Explanation :
Molecule : It is defined as the smallest particle in an element or a compound which has chemical properties of that element or a compound.
Molecules are made up of atoms and the atoms are bonded by the sharing of electrons.
The given molecules is,
The nitrogen trifluoride molecule is made up of two elements which are nitrogen and fluorine.
In the given molecules , there are 1 nitrogen atom and there are 3 fluorine atoms.
Hence, the number of atoms of fluoride present in one molecule of are, 3.
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Answer:- Formula of the hydrate is and it's name is Iron(III)sulfate pentahydrate.
Solution:- As per the given information, there is 18.4% water in the hydrate. If we assume the mass of the hydrate as 100 grams then there would be 18.4 grams of water and 81.6 grams of Iron(III)sulfate present in the hydrate.
Molar mass for Iron(III)sulfate is 399.88 gram per mol and the molar mass for water is 18.02 gram per mol.
We will calculate the moles of Iron(III)sulfate and water present in the compound on dividing their grams by their molar masses as:
=
=
Now, the next step is to calculate the mol ratio and for this we divide the moles of each by the least one of them means whose moles are less. Here, the moles of Iron(III)sulfate are less than moles of water. So, we divide the moles of each by 0.204.
= 1
= 5
There is 1:5 mol ratio between Iron(III)sulfate and water. So, the formula of the hydrate is and the name of the hydrate is Iron(III)sulfate pentahydrate.