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Kipish [7]
3 years ago
5

Why can filtration not be used to seperate a mixture of 2 liquids ​

Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
3 0

Answer:

Filtration works best when the solute isn't dissolve in the solvent. For instance, sand and water can be seperated through filtration because both compounds do not dissolve with each other. However, sugar and water would not be seperated through filtration as they dissolve with each other.

-google :)

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24 grams of magnesium metal reacts with 16 grams of oxygen gas to form magnesium oxide according to the law of conservation of m
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Suppose you burn a substance in the air (reactants) and produce smoke and ash (products). The law of conservation of mass states
Aleks04 [339]

Answer:

<u>The same as</u> can best fill the space

Explanation:

The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. For example, when wood burns, the mass of the soot, ashes, and gases, equals the original mass of the charcoal and the oxygen when it first reacted.

It shows that when wood burns, it combines with oxygen and changes not only to ashes, but also to carbon dioxide and water vapor. The gases float off into the air, leaving behind just the ashes. Suppose you had measured the mass of the wood before it burned and the mass of the ashes after it burned. Also suppose you had been able to measure the oxygen used by the fire and the gases produced by the fire. What would you find? The total mass of matter after the fire would be the same as the total mass of matter before the burning.

3 0
3 years ago
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When a compound containing cesium ions is heated in a Bunsen burner flame, photons with an energy of 4.30 x 10-19 J are emitted.
inessss [21]

<u>Answer:</u> The wavelength of the flame is 462 nm and color of cesium flame is blue.

<u>Explanation:</u>

To calculate the wavelength, we use Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

E = Energy of 1 photon = 4.30\times 10^{-19}J

h = Planck's constant = 6.625\times 10^{-34}J.s

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = ?

Putting values in above equation, we get:

4.30\times 10^{-19}=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{\lambda }\\\\\lambda=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{4.30\times 10^{-19}}=4.62\times 10^{-7}m=462nm

The range of wavelength of blue light lies in range of 500 nm - 435 nm

The calculated wavelength lies in the above range. So, the color of the cesium flame is 462 nm

Hence, the wavelength of the flame is 462 nm and color of cesium flame is blue.

6 0
3 years ago
In this part of the periodic table, what type of elements are in the group that includes elements c, o, and s?
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5 0
3 years ago
Please help, timed test, will give brainliest
OlgaM077 [116]

Answer:

The answer to your question is letter B

Explanation:

A.)                     2 AgCl + Na2S ⟶ 2 Ag2S + 2 NaCl

                Reactants           Elements              Products

                      2                         Ag                         4

                      2                          Cl                          2

                      2                          Na                         2

                      1                            S                           2

This reaction is unbalanced

B.)                       2 AgCl + Na2S ⟶ Ag2S + 2 NaCl

                Reactants           Elements              Products

                      2                         Ag                         2

                      2                          Cl                          2

                      2                          Na                         2

                      1                            S                           1

This reaction is balanced

C.)                         AgCl + Na2S ⟶ 2 Ag2S + 2 NaCl

                Reactants           Elements              Products

                      1                         Ag                         4

                      1                          Cl                          2

                      2                          Na                         2

                      1                            S                           2

This reaction is unbalanced

D.)                2 AgCl + 2 Na2S ⟶ Ag2S + NaCl

                Reactants           Elements              Products

                      2                         Ag                         4

                      2                          Cl                          1

                      4                          Na                         1

                      2                            S                          1

This reaction is unbalanced

4 0
3 years ago
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