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Schach [20]
3 years ago
7

jose buys a new moped. He travels 3km south and then 4 km east. How far does he need to go to get back to where he started?

Physics
2 answers:
slega [8]3 years ago
4 0

Answer: 5km by straight line, 7km by route.

Explanation:

The distance by route is 3km south and then 4km east, notice that the distances are perpendicular to each other, so the total distance traveled (by a straight line) is:

D = √((3km)^2 + (4km)^2) = √(9km^2 + 16km^2) = (√25)km = 5km

So the distance by a straight line that he needs to go back to where he started is 5km, and if he wants to get back by route, he must do 4km to the west and then 3km to the north, so a total of 7km

cupoosta [38]3 years ago
3 0
4km. its a trick question obviously lol
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resultant x = 2.5 cos 35 + 5.2 cos 22 = 6.87 km

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The resultant displacement is calculated using hypotenuse equation:

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The resultant angle is:

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y = 20.38 [m]

Explanation:

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Note: the negative sign of the equation means that the acceleration acts in the opposite direction to the movement of the body. And the final speed is zero, because when the body reaches the maximum height, the Stone does not move its speed has been reduced to its entirety.

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