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aleksley [76]
4 years ago
8

A sample of glucose, C6H12O6, contains 6.02 × 1022 atoms of carbon. How many moles of hydrogen atoms and how many moles of gluco

se does it contain.
Chemistry
2 answers:
Dima020 [189]4 years ago
3 0
Glucose  has    6  number  of  carbon  atoms,  12  atoms  of  oxygen  and   6  atoms  of  oxygen
The  total  number  of  glucose  atom is  24  atoms
The  atom  of  hydrogen is twice  that  of   carbon  
that  is (6.02 x10^22) x2=1.204 x10^23atoms
the  number  of  moles  of  hydrogen  is   solved  as   follows
1mole  =  6.02x10^23 atoms  what   about  1.204 x10^23=
{(1.204x10^23)/(6.02 x10^23)}=0.2moles
The  moles  of  glucose
1   atom  of   glucose=  6.02 x10^22  x4 =2.408 x10^23  atoms
moles= { (2.48 x10^23)/(6.02  x10^23)}=0.41moles

kenny6666 [7]4 years ago
3 0

Because of the chemical formula of glucose we can infer the rations of each atom from one another, we can see that every 6 atoms of carbon there are 12 atoms of hydrogen. Therefore, there is twice as much hydrogen than carbon or <span>12.04 × 10^22 atoms or 0.2 moles of hydrogen in the sample. Following this we can infer that a glucose molecule needs 6 atoms of carbon, therefore we divide the amount of carbon by 6, and converting it into moles we will get 0.0167 moles of glucose.</span>

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The answer to your question is   P2 = 280 mmHg

Explanation:

Data

Pressure 1 = P1 = 400 mmHg

Volume 1 = V1 = 1.75 L

Pressure 2 = ?

Volume 2 = 2.5 L

Process

1.- Use Boyle's law to solve this problem

                  P1V1 = P2V2

-Solve for P2

                     P2 = P1V1 / V2

2.- Substitution

                    P2 = (400)(1.75) / 2.5

3.- Simplification

                   P2 = 700 / 2.5

4.- Result

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A compound is found to contain 13.65 % carbon and 86.35 % fluorine by mass. To answer the question, enter the elements in the or
Nimfa-mama [501]

Answer: The molecular formula will be CF_4

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C= 13.65 g

Mass of F = 86.35 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{13.65g}{12g/mole}=1.138moles

Moles of F=\frac{\text{ given mass of F}}{\text{ molar mass of F}}= \frac{86.35g}{19g/mole}=4.545moles

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For F = \frac{4.545}{1.138}=4

The ratio of C : F= 1: 4

Hence the empirical formula is CF_4

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