All categories

3 years ago

When organizing your narrative, what are the 3 sections that make up a story (planning the specific order)

Chemistry

1 answer:

Sveta_85 [38]3 years ago

3 0

Answer:

#1 Exposition

#2 Background information

#3 Complication

this is right unless you're speaking of theme plot conflict climax falling action or conclusion

You might be interested in

In the reaction of silver nitrate with sodium chloride, how many grams of silver chloride will be produced from 100. g of silver

pantera1 [17]

Answer:

The mass in grams of silver chloride, AgCl produced is 84.37 grams

Explanation:

The chemical equation for the reaction is given as follows;

AgNO₃ + NaCl → AgCl + NaNO₃

The mass of silver nitrate, AgNO₃, in the reaction = 100.0 g

Therefore, 1 Mole of AgNO₃ produces 1 mole of AgCl,

The molar mass of silver nitrate, AgNO₃ = 169.87 g/mol

The number of moles of silver nitrate, AgNO₃, in the reaction = 100/169.87 moles

The number of moles of silver nitrate, AgNO₃, in the reaction ≈ 0.59 moles

Since 1 mole of AgNO₃ produces 1 mole of AgCl, 0.59 moles of AgNO₃ produces 0.59 moles of AgCl

The number of moles of silver chloride, AgCl produced = 0.59 moles

The molar mass of silver chloride, AgCl = 143.32 g/mol

Therefore;

The mass of silver chloride, AgCl produced = The number of moles of silver chloride, AgCl produced × The molar mass of silver chloride, AgCl

Which gives;

The mass of silver chloride, AgCl produced = 143.32 g/mol × 0.59 moles = 84.37 g

The mass of silver chloride, AgCl produced = 84.37 g.

7 0

4 years ago

(-5)+(+7)-(-4) + (+12) A 8 B 10 C 18 d 20

Vladimir79 [104]

Answer:

C-18

Explanation:

Step one follow order of operations

Add and subtract from left to right(-5)+(7)=2-(-4)+(12)

STEP 2

Apply negative Rule -(-4)=+4=2+4+(12)

then add 2+4+12=18

5 0

3 years ago

Which of the following are true of phases?Check all that apply.A.The particles in a liquid are in a fixed location.B.Gases have

saw5 [17]

Answer:

The answers are options b , c and d.

Hope this helps.

7 0

3 years ago

What is the correct name for Mn(NO3),

kupik [55]

Answer:

Manganese trinitrate or manganese(III) nitrate

Explanation:

6 0

3 years ago

If 12.5 grams of strontium hydroxide is reacted with 150 mL of 3.5 M carbonic acid, identify the limiting reactant.

kiruha [24]

Answer:

Sr(OH)₂ will be the limiting reagent.

Explanation:

First of all, you should know the following balanced chemical equation:

2 H₂CO₃ + 2 Sr(OH)₂ → 4 H₂O + Sr₂(CO₃)₂

The balanced equation is based on the Law of Conservation of Mass, which says that matter cannot be created or destroyed. Therefore, the number of each type of atom on each side of a chemical equation must be the same.

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use the reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction). By stoichiometry the following amounts in moles react:

strontium hydroxide: 2 moles
carbonic acid: 2 moles

Now, you know the following masses of the elements:

Sr: 87.62 g/mole
O: 16 g/mole
H: 1 g/mole

So the molar mass of strontium hydroxide is:

Sr(OH)₂= 87.62 g/mole + 2*(16 g/mole + 1 g/mole)= 121.62 g/mole

You apply the following rule of three, if 121.62 grams of hydroxide are present in 1 mole, 12.5 grams in how many moles are they?

$moles of strontium hydroxide=\frac{12.5 grams*1 mole}{121.62 grams}$

moles of hydroxide= 0.103 moles

On the other hand, you have 150 ml of 3.5 M carbonic acid. Since molarity is the concentration of a solution expressed in the number of moles dissolved per liter of solution, you can apply the following rule of three: if in 1 L there are 3.5 moles of carbonic acid, in 0.150 L (being 1 L = 1000 mL, 0.150 L = 150 mL) how many moles of acid are there?

$molesofcarbonicacid=\frac{0.150 L*3.5 moles}{1 L}$

moles of carbonic acid= 0.525 moles

Finally, to calculate the limiting reagent, you can use a simple rule of three as follows: if by stoichiometry 2 mole of strontium hydroxide reacts with , how much moles of carbonic acid will be needed if 0.103 moles of strontium hydroxide react?

$molesofcarbonicacid=\frac{0.103 moles of strontium hydroxide*2 moles of carbonic acid}{2 moles of strontium hydroxide}$

moles of carbonic acid= 0.103 moles

But 0.525 moles are available. Since more moles are available than you need to react with 0.103 moles of strontium hydroxide, Sr(OH)₂ will be the limiting reagent.

7 0

3 years ago