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3 years ago

When organizing your narrative, what are the 3 sections that make up a story (planning the specific order)

Chemistry

1 answer:

Sveta_85 [38]3 years ago

3 0

Answer:

#1 Exposition

#2 Background information

#3 Complication

this is right unless you're speaking of theme plot conflict climax falling action or conclusion

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For C2H5OH (liquid)So = 161 J/K.mol; for C2H5OH (gas)So = 282.6 J/K.mol. What is ΔS if 92 g of C2H5OH is evaporated?

ira [324]

Tye answer is 111.5 j/k

6 0

3 years ago

A mixture of copper and tin would be called _________.

Alexus [3.1K]

It would be called an alloy.

5 0

3 years ago

How many grams of water can be formed when 80 grams of sodium hydroxide (NaOH) reacts with an excess of sulfuric acid, H2SO4, in

podryga [215]

Answer:

36g of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction:

2NaOH + H2SO4 —> Na2SO4 + 2H2O

Next, we shall determine the mass of NaOH that reacted and the mass of H2O produced from the balanced equation. This is illustrated below:

Molar mass of NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the balanced equation = 2 x 40 = 80g

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O from the balanced equation = 2 x 18 = 36g.

From the balanced equation above, we can see evidently that:

80g of NaOH reacted to produce 36g of H2O.

5 0

3 years ago

ph ch3 h2nnh koh The Wolff-Kishner reaction involves the reaction of an aldehyde/ketone with hydrazine in the presence of KOH. T

Tatiana [17]

Hope this was helpful!

6 0

3 years ago

What is the percent yield if 107.50 g NH3 reacts with excess O2 according to the

Maksim231197 [3]

Answer:

81.59%

Explanation:

4NH₃ + 5O₂ → 4NO + 6H₂O

First we convert 107.50 g of NH₃ into moles, using its molar mass:

107.50 g NH₃ ÷ 17 g/mol = 6.32 mol NH₃

Now we calculate how many moles of NO would have been formed by the complete reaction of 6.32 moles of NH₃:

6.32 mol NH₃ * $\frac{4molNO}{4molNH_3}$ = 6.32 mol NO

Then we convert 6.32 moles of NO to grams, using its molar mass:

6.32 mol NO * 30 g/mol = 189.60 g NO

Finally we calculate the percent yield:

154.70 g / 189.60 g * 100% = 81.59%

8 0

3 years ago