Pajamas
Out fit for each day + 2 extra
Athletic clothes
Light hoodie
Bathing suit + cover up
Underwear
Socks
Bra's
Sunscreen
Moisturizer
Makeup
Makeup remover
Shampoo + conditioner
Shaving cream
Razor
Medicine (pain meds, etc.)
Lotion
Chapstick
Retainer (if you have 1)
Tooth brush + toothpaste
Deodorant
Monthly Items
Phone charger
Computer + computer charger
Camera + camera charger
Headphones
Water bottle
Snacks
Perfume
Book
Glasses
Purses
Jewelry
Watch
Wallet
Hat
Sunglasses
Hand sanitizer
Tennis shoes
Walking shoes
Flip flops
Blow dryer
Straightner
Hair clips
Hair ties
Hair brush
Hair spray
Heat protection
Have music + shows/ movies downloaded
Hope this helps you take off anything you don't want or anything you don't need
There are:
3.41 moles of C
4.54 moles of H
3.40 moles of O.
Why?
To solve the problem, the first thing that we need to do is to write the chemical formula of the ascorbic acid.
Now, we know that there are 100 grams of the compound, so, the masses of each element will represent the percent in the compound.
We have that:
To know the percent of each element, we need to to the following:
So, we know that for the 100 grams of the compound, there are:
40.92 grams of C
4.58 grams of H
54.49 grams of O
We know the molecular masses of each element:
Now, to calculate the number of moles of each element, we need to divide the mass of each element by the molecular mass of each element:
Hence, we have that there are 3.41 moles of C, 4.54 moles of H, and 3.40 moles of O.
Have a nice day!
Answer:
pH = 4
Solution is acidic
Explanation:
Given data;
Hydronium ion concentration = 1 × 10⁻⁴ M
pH of solution = ?
Solution:
pH = -log [H₃O⁺]
pH = -log [ 1 × 10⁻⁴ ]
pH = 4
According to pH scale the pH 7 is neutral while the pH less than 7 is acidic and greater than 7 is basic. The given solution has pH 4 it means solution is acidic.
Answer:
Option E. Zirconium
Explanation:
From the question given above, the following data were obtained:
Length of side (L) of cube = 0.2 cm
Mass (m) of cube = 52 mg
Name of the unknown metal =?
Next, we shall determine the volume of the cube. This can be obtained as follow:
Length of side (L) of cube = 0.2 cm
Volume (V) of the cube =?
V = L³
V = 0.2³
V = 0.008 cm³
Next, we shall convert 52 mg to g. This can be obtained as follow:
1000 mg = 1 g
Therefore,
52 mg = 52 mg × 1 g / 1000 mg
52 mg = 0.052 g
Thus, 52 mg is equivalent to 0.052 g.
Next, we shall determine the density of the unknown metal. This can be obtained as follow:
Mass = 0.052 g.
Volume = 0.008 cm³
Density =?
Density = mass / volume
Density = 0.052 / 0.008
Density of the unknown metal = 6.5 g/cm³
Comparing the density of the unknown metal i.e 6.5 g/cm³ with those given in table in the above, we can conclude that the unknown metal is zirconium
214, 84 Po ----Beta decay
