Answer: 1s2 2s2 2p3
Explanation:
atomic number is 7 hence it shuld be 2,5 if numerically.. tho the standard notation is the above giver answer
Answer:
See explanation below
Explanation:
The question is incomplete, however, I found a question very similar to this, and I'm assuming this is the question you are asking to answer. If it's not, please tell me which one it is. Here's a tip for you to get an idea of how to solve.
Picture 1, would be the original question. Picture 2 is the answer of it.
Now, This is a E1 reaction where this type of reactions are taking place in two steps. The first step is the formation of the carbon cation, this step is always slow. The secon step is the addition of a nucleophyle, or, in this case, formation of a pi bond, and we get a alkene.
Hope this can help you
Answer:

Explanation:
We are asked to find the new volume of a gas after a change in temperature. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula for this law is:

The gas was heated to 150 degrees Celsius and had a volume of 1587.4 liters.

The temperature was 100 degrees Celsius, but the volume is unknown.

We are solving for the volume at 100 degrees Celsius, so we must isolate the variable V₂. It is being divided by 100°C and the inverse of division is multiplication. Multiply both sides of the equation by 100°C.


The units of degrees Celsius cancel.



The original measurement of volume has 5 significant figures, so our answer must have the same. For the number we calculated, that is the tenth place. The 6 in the hundredth place to the right tells us to round to 2 up to a 3.

The volume of the gas at 100 degrees Celsius is approximately <u>1058.3 liters.</u>
Answer:
expected configuration for Cr is
1s2 2s2 2p6 3s2 3p6 4s2 3d4
but in real, it is
1s2 2s2 2p6 3s2 3p6 4s1 3d5
electron from 4s orbital jumps to 3d orbital to get stable configuration.
so the last electron comes in 3d orbital as filling of 3d takes place after filling of 4s orbital.
Hence,quantum numbers for last electron in Cr is :-
n = 3
l = 2
m = +2
s = +1/2
Explanation: