Displacement is the area under the velocity/time graph. So for example this object's displacement in the first 3 seconds is (1/2)(3sec)(12.5 m/s)= 18.75m. (and then it starts backing up, displacement decreasing, after 3sec when velocity is negative).
But This object is never speeding up. Its velocity is smoothly decreasing at (25/6) m/s^2 (the slope of the graph). So the answer to the question is actually zero.
Answer:
4.14 cm.
Explanation:
Given,
For Coil 1
radius of coil, r₁ = 5.6 cm
Magnetic field, B₁ = 0.24 T
For Coil 2
radius of coil, r₂ = ?
Magnetic field, B₂ = 0.44 T
Using formula of maximum torque

Since both the coil experience same maximum torques
now,





Radius of the coil 2 is equal to 4.14 cm.
Where is the cube I don't see any picture?
Answer:
<h2>Tt will take 4.04 seconds</h2>
Explanation:
In this problem/exercise, we are going to apply the newtons first equation of motion to solve for the time taken
Given that
final velocity= 3.4m/s
initia velocity u= 0m/s
deceleration= 0.84 m/s^2
time t= ?
applying
v=u+at
Substituting our given data into the expression above we have
3.4=0+0.84t
3.4=0.84t
divide both sides by 0.84 we have
3.4/0.84= t
t= 4.04 seconds
As we know that Nth harmonic of the string is given by

now here we will have




now from above formula we have


now for first harmonic N = 1

for second harmonic N = 2

for third harmonic N = 3