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Gekata [30.6K]
3 years ago
5

Calculate the volume in ml of 0.200 M na2co3 needed to produce 2.00 g of caco3 there is an excess of cacl2

Chemistry
1 answer:
UkoKoshka [18]3 years ago
8 0

Answer:

V=100mL

Explanation:

Hello.

In this case, since the chemical reaction is:

Na_2CO_3+CaCl_2\rightarrow  CaCO_3+2NaCl

We next compute the moles of sodium carbonate from the 2.00 grams of calcium carbonate via their 1:1 mole ratio in the chemical reaction:

n_{Na_2CO_3}=2.00gCaCO_3*\frac{1molCaCO_3}{100.09gCaCO_3}*\frac{1molNa_2CO_3}{1molCaCO_3}  \\\\n_{Na_2CO_3}=0.0200molNa_2CO_3

Thus, by knowing the molarity, we compute the volume:

M=\frac{n}{V}\\ \\V=\frac{n}{M}=\frac{0.0200mol}{0.200mol/L}\\  \\V=0.100L*\frac{1000mL}{1L}\\ \\V=100mL

Best regards.

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