Explanation:
given,
mass of one planet (m1)=2*10^23 kg
mass of another planet (m2)=5*10^22kg
distance between them(d)=3*10^16m
gravitational constant(G)=6.67*10^-11Nm^2kg^-2
gravitational force between them(F)=?
we know,
F=Gm1m2/d^2
or, F=6.67*10^-11*2*10^23*5*10^22/(3*10^16)^2
or, F=6.67*2*5*10^-11+23+22/3*3*10^32
or, F=66.7*10^34/9*10^32
or, F=7.41*10^34-32
•°• F=7.41*10^2
thus, the gravitational force between them is 7.14*10^2
Answer:
The radius of coil 2 = 2.7 cm
Explanation:
The number of coils = 2
It is given that both carry equal current and rotates in the magnetic field.
The given radius of coil 1 = 4.0 cm
Coil 1 rotates = 0.21 T field
Coil 2 rotates = 0.45 T filed.
The radius of coil 2 need to be calculated.
Torque action on dipole is given by
here T1 = T2

The correct answer would be C. it moves at a constant speed. The troposphere(the layer our weather is in) is not nearly high enough for gravity to be different at different altitudes.
Answer:
I dont see a picture where is it?
Explanation:
I cannot see anything L question Luestion
Answer: a) Mr = 2.4×10^-4kg/s
V = 34.42m/a
b) E = 173J
Ø = 2693.1J
c) Er = 0.64J/s
Explanation: Please find the attached file for the solution