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bonufazy [111]
3 years ago
15

A sample of Element X is found to contain 67.25% of isotope type 1 (85.91) and 32.75% of isotope type 2 (87.91). Calculate the a

verage atomic mass.
Chemistry
1 answer:
KengaRu [80]3 years ago
5 0

Answer:

The average atomic mass is 86.565

Explanation:

An element's average atomic mass is the sum of the products of the masses of the isotopes of the element and their percentage abundance divided by 100

The average atomic mass of the Element X is given as follows;

Isotope type 1 (85.91) ×

Isotope {}   Abundance (%)        Mass         /100        Portion of average mass

Type 1 {}             67.25       ×       85.91      ÷  100        57.774475

Type 2 {}            32.75       ×       87.91       ÷  100       28.790525

{}                                 Average atomic mass         =  86.565

The average atomic mass = 86.565.

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5 0
3 years ago
The Ksp for calcium fluoride, CaF2, is 1.5 x 10-10. a) Excess solid calcium fluoride is added to 1.00 L of pure water. Calculate
solniwko [45]

Answer:

a) [ Ca2+ ] = 3.347 E-4 mol/L

b) [ Ca2+ ] = 1.5 E-8 mol/L

Explanation:

  • CaF2 ↔ Ca2+  +  2F-

          S             S          2S......in the equilibrium

⇒ Ksp = 1.5 E-10 = [ Ca2+ ] * [ F- ]² = S * ( 2S )² = 4S³

⇒ S = ∛ ( 1.5 E-10 / 4 )

⇒ S = ∛ 3.75 E-11

⇒ S = 3.347 E-4 mol/L

⇒ [ Ca2+ ] = S = 3.347 E-4 mol/L

b) NaF ↔ Na+  +  F-

  0.10 M    0.10     0.10

  • CaF2 ↔,Ca2+  +    2F-

         S             S         2S + 0.10

⇒ Ksp = 1.5 E-10 = [ Ca2+ ] * [ F- ]² = S * ( 2S + 0.10 )²

∴∴ the Concentration: 0.10 M >>>> Ksp ( 1.5 E-10 ), son we can despise S as adding.

⇒ 1.5 E-10 = S * ( 0.10 )² = 0.01 S

⇒ S = 1.5 E-10 / 0-01

⇒ S = 1.5 E-8 mol/L

⇒ [ Ca2+ ] = S = 1.5 E-8 mol/L

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Chlorine is more electronegative than iodine. The electronegativity of chlorine is 3.16. The electronegativity of iodine is 2.66.

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7 0
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How do water molecules dissolve a salt?
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