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RoseWind [281]
3 years ago
9

Which equation shows the beta decay of a transuranium element

Chemistry
1 answer:
GalinKa [24]3 years ago
5 0

1) Since you have not provided the equations to select the right one, I am going to explain you the relevant facts that are used to solve this question.



2) The transuranium elements are the chemiical elements with atomic number greater than that of the uranium.


The atomic number of uranium is 92. So, the transuranium elements are the elements with atomic number 93 or greater.



This are some of the transuranium elements:


Neptunio - 93

Plutonium - 94

Americium - 95

Curium - 96

Berkelium - 97

Californium - 98

Einstenium - 99



And so all the known elements (the last one is the 118).



3) In a nuclear reaction the total mass number ( shown as superscript to the left of the symbol) and total atomic number (shown as subscript to the left of the symbol) are conserved.



4) Beta decay is the release of a beta particle, which is an electron (considered massles and with charge - 1). So, the beta decay is represented with the symbol:


0

  β, which means 0 mass and charge - 1.

-1



5) This is, then, an example of a β decay equation for one transuranium element:


239              239            0

      Np    →         Pu   +      β

  93                94            -1



As you see 239 = 239 + 0 and 93 = 94 - 1, showing that the total mass number ( shown as superscript to the left of the symbol) and the total atomic number (shown as subscript to the left of the symbol) are conserved.


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Choose the correct net ionic equation for the reaction (if a reaction occurs) between CaCl2 and AgNO3: Group of answer choices
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2Ag⁺(aq) + 2Cl⁻(aq) -> 2AgCl(s)

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Silver nitrate and calcium chloride will react in a double displacement reaction (which has to produce a precipitate, a gas, or water to have a reaction).

This reaction will produce a silver chloride precipitate and a solution of calcium nitrate.

The reaction will be 2AgNO3(aq) + CaCl2(aq) -> 2AgCl(s) + Ca(NO3)2(aq)

To write a net ionic equation:

1. Write the balanced molecular equation.

   2AgNO3 + CaCl2 -> 2AgCl(ppt) + Ca(NO3)2

2. Write the balanced complete ionic equation.

To write the complete ionic equation:

- Start with a balanced molecular equation.

2AgNO3(aq) + CaCl2(aq) -> 2AgCl(s) + Ca(NO3)2(aq)

- Break all soluble strong electrolytes (compounds with (aq) beside them) into their ions

       indicate the correct formula and charge of each ion

       indicate the correct number of each ion

       write (aq) after each ion

- Bring down all compounds with (s), (l), or (g) unchanged.

2Ag⁺(aq) + 2NO³⁻(aq) + Ca²⁺(aq) + 2Cl⁻(aq) -> 2AgCl(s) + Ca²⁺(aq) + 2NO³⁻(aq)

3. Cross out the spectator ions that are present. Spectator ions are ions that are present in the reaction mixture but do not participate in it. You can recognize spectator ions by looking for ions that are present on both sides of the equation.

4. Write the "leftovers" as the net ionic equation.

2Ag⁺(aq) + 2Cl⁻(aq) -> 2AgCl(s)

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