what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees
1 answer:
Answer:
The horizontal component of the vector ≈ -16.06
The vertical component of the vector ≈ 19.15
Explanation:
The magnitude of the vector, = 25 units
The direction of the vector, θ = 130°
Therefore, we have;
The horizontal component of the vector, Rₓ = × cos(θ)
∴ Rₓ = 25 × cos(130°) ≈ -16.06
<em>The horizontal component of the vector, Rₓ ≈ -16.06</em>
The vertical component of the vector, R =
× sin(θ)
∴ R = 25 × sin(130°) ≈ 19.15
<em>The vertical component of the vector, R</em><em> ≈ 19.15</em>
(The vector, R = Rₓ + R
= Rₓ·i + R
·j
∴ ≈ -16.07·i + 19.15j)
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Complete Question
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The mass of the bridge per unit length is
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Generally the amplitude of the section considered is mathematically represented as
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