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3 years ago

what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees

Physics

1 answer:

AlekseyPX3 years ago

5 0

Answer:

The horizontal component of the vector ≈ -16.06

The vertical component of the vector ≈ 19.15

Explanation:

The magnitude of the vector, $\left | R \right |$ = 25 units

The direction of the vector, θ = 130°

Therefore, we have;

The horizontal component of the vector, Rₓ = $\left | R \right |$ × cos(θ)

∴ Rₓ = 25 × cos(130°) ≈ -16.06

<em>The horizontal component of the vector, Rₓ ≈ -16.06</em>

The vertical component of the vector, R $_y$ = $\left | R \right |$ × sin(θ)

∴ R $_y$ = 25 × sin(130°) ≈ 19.15

<em>The vertical component of the vector, R</em> $_y$ <em> ≈ 19.15</em>

(The vector, R = Rₓ + R $_y$

$\underset{R}{\rightarrow}$ = Rₓ·i + R $_y$ ·j

∴ $\underset{R}{\rightarrow}$ ≈ -16.07·i + 19.15j)

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$Q = m[c_w (T_i - T_b) + m* c__{L}} + m* c__{S}} (T_f - T_b)]$

Then substituting the value

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what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees​

what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees