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umka2103 [35]
3 years ago
7

what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees​

Physics
1 answer:
AlekseyPX3 years ago
5 0

Answer:

The horizontal component of the vector ≈ -16.06

The vertical component of the vector ≈ 19.15

Explanation:

The magnitude of the vector, \left | R \right | = 25 units

The direction of the vector, θ = 130°

Therefore, we have;

The horizontal component of the vector, Rₓ = \left | R \right | × cos(θ)

∴ Rₓ = 25 × cos(130°) ≈ -16.06

<em>The horizontal component of the vector, Rₓ ≈ -16.06</em>

The vertical component of the vector, R_y = \left | R \right | × sin(θ)

∴  R_y = 25 × sin(130°) ≈ 19.15

<em>The vertical component of the vector, R</em>_y<em> ≈ 19.15</em>

(The vector, R = Rₓ + R_y

\underset{R}{\rightarrow} = Rₓ·i + R_y·j

∴ \underset{R}{\rightarrow} ≈ -16.07·i + 19.15j)

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Why is 30% recommended as the minimum Michelson contrast?
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Answer:

Explained

Explanation:

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m= \frac{I_{max}-I{min}}{I_{max}+I{min} }

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we know that

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3 years ago
What is 28 degrees Celsius converted to Fahrenheit?
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3 years ago
Read 2 more answers
Let the masses of blocks A and B be 4.50 kg and 2.00 kg , respectively, the moment of inertia of the wheel about its axis be 0.4
Free_Kalibri [48]

Answer:

Accelerations of both the sides is 0.6125 m/s^{2}, A moves downwards whereas B moves upwards.

\alpha=6.125 rad/s^{2}

Tension on side A = 4.5 × g= 44.1 m/s^{2}

Tension on side B= 2.0 × g=  19.6 m/s^{2}

Explanation:

As both, the blocks A and B are attached due to the constraint they can only possess a single acceleration a.

Observe the figure attached, let the tension with Block A be T_{2} and the tension attached with Block B be T_{1} .

Tensions will be only be due to the weight of the blocks as no other force is present.

T_{2} = 4.5 × g= 44.1 m/s^{2}

T_{1} = 2.0 × g=  19.6 m/s^{2}

Now, lets make a torque equation about the center of the wheel and find the alpha

T_{2}×R- T_{1}×R= MI( Moment of Inertia of Wheel)× Alpha

where, R= Radius of the wheel=0.100m  and

           Alpha(\alpha)= Angular acceleration of the wheel

MI of the wheel= 0.400 kg/m^{2}

(44.1-19.6)R=0.400\alpha

\alpha = \frac{24.5 * 0.100}{0.400}

\alpha=6.125 rad/s^{2}

Acceleration = R ×\alpha

                    = 0.1 * 6.125

                    =0.6125 m/s^{2}

Accelerations of both the sides is 0.6125 m/s^{2}, A moves downwards whereas B moves upwards.

7 0
3 years ago
Lightning flashes and you hear a thunder clap for seconds later. the velocity of sound is 340 m/s. how far away did lightning st
kondaur [170]

Answer:

For metric-system conversions, follow this method: Sound travels at about 340 m/s, so multiply the number of seconds you counted by 340, and you'll know how many meters away lightning struck. A three-second count, then, would place the lightning strike about 1,020 m away, or roughly 1 km.

Explanation:

hope it hep and if it doesnt sorry

3 0
3 years ago
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