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umka2103 [35]
3 years ago
7

what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees​

Physics
1 answer:
AlekseyPX3 years ago
5 0

Answer:

The horizontal component of the vector ≈ -16.06

The vertical component of the vector ≈ 19.15

Explanation:

The magnitude of the vector, \left | R \right | = 25 units

The direction of the vector, θ = 130°

Therefore, we have;

The horizontal component of the vector, Rₓ = \left | R \right | × cos(θ)

∴ Rₓ = 25 × cos(130°) ≈ -16.06

<em>The horizontal component of the vector, Rₓ ≈ -16.06</em>

The vertical component of the vector, R_y = \left | R \right | × sin(θ)

∴  R_y = 25 × sin(130°) ≈ 19.15

<em>The vertical component of the vector, R</em>_y<em> ≈ 19.15</em>

(The vector, R = Rₓ + R_y

\underset{R}{\rightarrow} = Rₓ·i + R_y·j

∴ \underset{R}{\rightarrow} ≈ -16.07·i + 19.15j)

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