Question

what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees​

Answer 1

Answer:

The horizontal component of the vector ≈ -16.06

The vertical component of the vector ≈ 19.15

Explanation:

The magnitude of the vector, $\left | R \right |$ = 25 units

The direction of the vector, θ = 130°

Therefore, we have;

The horizontal component of the vector, Rₓ = $\left | R \right |$ × cos(θ)

∴ Rₓ = 25 × cos(130°) ≈ -16.06

The horizontal component of the vector, Rₓ ≈ -16.06

The vertical component of the vector, R$_y$ = $\left | R \right |$ × sin(θ)

∴  R$_y$ = 25 × sin(130°) ≈ 19.15

The vertical component of the vector, R$_y$ ≈ 19.15

(The vector, R = Rₓ + R$_y$

$\underset{R}{\rightarrow}$ = Rₓ·i + R$_y$·j

∴ $\underset{R}{\rightarrow}$ ≈ -16.07·i + 19.15j)