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Aliun [14]
3 years ago
5

Suppose that you have a supply of a 40% solution of alcohol and a 60% solution of alcohol. how many quarts of each should be mix

ed to produce 100 quarts that is 50% alcohol?
Chemistry
1 answer:
Maru [420]3 years ago
4 0
<span>50 quarts of 60% solution and 50 quarts of 40% solution. You want a total of 100 quarts, so we'll use the following expressions x = amount of 60% solution (100 - x) = amount of 40% solution. The total amount of alcohol will be 0.6x + 0.4(100-x) We want the final result to be 100 quarts of 50% solution, so we express that as 0.5 * 100 Now we set them equal to each other, and solve for x 0.6x + 0.4(100-x) = 0.5 * 100 Distribute the .4 0.6x + 0.4*100 - 0.4x = 0.5 * 100 0.6x + 40 - 0.4x = 50 Subtract 40 from both sides and combine the x terms 0.2x = 10 Divide both sides by 0.2 x = 50 Now we know we need 50 quarts of the 60% solution. And we need (100 - 50) = 50 quarts of the 40% solution as well.</span>
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B

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a. Sn or Si ⇒ Sn

b. Br or Ga ⇒ Ga

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d. Se or Sn ⇒ Sn

Explanation:

The larger atom has a larger atomic radius. We have to consider how varies the atomic radius for chemical elements in the Periodic Table. In a group (column), the atomic radius increases from top to bottom while in a period (file), it increases from right to left.

a. Sn or Si ⇒ Sn

They are in the <u>same group</u>. Sn is on the top, so it has a larger atomic radius.

b. Br or Ga ⇒ Ga

They are in the <u>same period</u>. Ga is located at the left so it has a larger atomic radius.

c. Sn or Bi ⇒ similar

They are not in the same group neither the same period. Bi is located more at the bottom, so it would be larger than Sn, but Bi is also at the right side, so it would be smaller than Bi. Thus, they have comparable sizes.

d. Se or Sn⇒ Sn

They are not in the same group neither the same period. Se is located at the top and right side compared to Sn, so Sn is the larger atom.

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