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AleksandrR [38]
3 years ago
12

Did i draw the tangent line correctly?​

Physics
1 answer:
Jet001 [13]3 years ago
8 0

Answer:

yes i belevie so

Explanation:

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A man ties one end of a strong rope 8.17 m long to the bumper of his truck, 0.524 m from the ground, and the other end to a vert
Kamila [148]

Answer:

2442.5 Nm

Explanation:

Tension, T = 8.57 x 10^2 N

length of rope, l = 8.17 m

y = 0.524 m

h = 2.99 m

According to diagram

Sin θ = (2.99 - 0.524) / 8.17

Sin θ = 0.3018

θ = 17.6°

So, torque about the base of the tree is

Torque = T x Cos θ x 2.99

Torque = 8.57 x 100 x Cos 17.6° x 2.99

Torque = 2442.5 Nm

thus, the torque is 2442.5 Nm.

8 0
4 years ago
Which scientific phenomenon helps scientists determine the chemical composition of some stars?
ser-zykov [4K]
The correct option is DISPERSION OF LIGHT AS IT ENTERS EARTH'S ATMOSPHERE. Scientists use astronomical spectrometer to analyse the composition of the sun and the stars. Astronomical spectrometer works on the basis of dispersion of light as it enters the earth's atmosphere.
6 0
3 years ago
Read 2 more answers
Suppose you have a pendulum clock which keeps correct time on Earth(acceleration due to gravity = 1.6 m/s2). For ever hour inter
kaheart [24]

The moon clock is A) (9.8/1.6)h compared to 1 hour on Earth

Explanation:

The period of a simple pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration of gravity

In this problem, we want to compare the period of the pendulum on Earth with its period on the Moon. The period of the pendulum on Earth is

T_e=2\pi \sqrt{\frac{L}{g_e}}

where

g_e = 9.8 m/s^2 is the acceleration of gravity on Earth

The period of the pendulum on the Moon is

T_m=2\pi \sqrt{\frac{L}{g_m}}

where

g_m = 1.6 m/s^2 is the acceleration of gravity on the Moon

Calculating the ratio of the period on the Moon to the period on the Earth, we find

\frac{T_m}{T_e}=\frac{g_e}{g_m}=\frac{9.8}{1.6}

Therefore, for every hour interval on Earth, the Moon clock will display a time of

A) (9.8/1.6)h

#LearnwithBrainly

6 0
3 years ago
A gun can fire a bullet at 540 m/s. If the gun is aimed at an angle of 55o above the horizontal and fired, what will be the hori
lisabon 2012 [21]

Answer:

Explanation:

The <u>initial</u> vertical velocity is 540sin55° = 442.342103... 442 m/s

The <u>initial</u> horizontal velocity is 540cos55° = 309.731275... 310 m/s

In the real world, both initial velocities would be reduced by air resistance and vertical velocity will be altered by gravity.

5 0
3 years ago
A stretched spring has 5184 J of elastic potential energy and a spring constant of 16,200 N/m. What is the displacement of the s
Ira Lisetskai [31]
The elastic potential energy (Ep) is given by Ep =  \frac{1}{2}*k*x^2

Data:
Ep = 5184 J
k = 16200 N/m
x (displacement) = ?

Solving:
Ep = \frac{1}{2}*k*x^2
5184 = \frac{1}{2}*16200*x^2
5184*2 = 16200x^2
10368 = 16200x^2
16200x^2 = 10368
x^2 =  \frac{10638}{16200}
x^2 = 0.64
x =  \sqrt{0.64}
\boxed{\boxed{x = 0.8\:m}}\end{array}}\qquad\quad\checkmark

8 0
4 years ago
Read 2 more answers
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