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vladimir2022 [97]
2 years ago
11

Suppose we have a space ship orbiting the earth. What must happen in order for the spaceship to leave orbit and fall back toward

earth?
The spaceship will fall back toward earth on its own but you have to just wait for it to fall.

The spaceship's forward motion must be slowed down so the earth's gravitational pull on it will be stronger than the ship's forward motion.

The spaceship's forward motion must be sped up so the earth's gravitational pull on it will be weaker than the ship's forward motion.

It is not possible for a spaceship orbiting the earth to leave orbit and fall back to earth once it is in orbit.
Physics
2 answers:
professor190 [17]2 years ago
8 0
It’s option 2
Hope it will help you:)
sdas [7]2 years ago
3 0

Answer:

#2) The spaceship's forward motion must be slowed down so the earth's gravitational pull on it will be stronger than the ship's forward motion.

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The beam is refracted at 53.17-degree angle (asin 0.800414 = 53.17-degree). This problem can be solved by using the Snell's Law which described the refracted beam angle which traveled through a different media, in this case, through water and air. The formula of Snell's Law is stated as n1 sin θ1= n2 sin θ2. In this formula n1 is the refraction index of medium 1, θ1 is the normal light angle in the medium 1, n2 is the refraction index of medium 2, and θ2 is the normal light angle in the medium 2<span>. </span>
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3 years ago
If the releases 39.4 kj of energy, how many kilocalories does it release? (1 cal = 4.184 j) (round off answer to 2 decimal place
REY [17]

By using unit conversion, the energy released in kilocalories is 9.42 kcal.

We need to know about unit conversion to solve this problem. There are several energy units which able to explain how much the energy is such as calories and joule. The energy unit can be converted to another unit by unit conversion. The unit conversion of calorie to joule is

1 cal = 4.184 joule

From the question above, we know that

E = 39.4 kJ

By using the unit conversion, we can convert the energy into calorie

E = 39.4 kJ

E = 39.4 x 10³ J

E = 39.4 x 10³ / 4.184 cal

E = 9.42 x 10³ cal

E = 9.42 x 10³ /10³  kcal

E = 9.42 kcal

Hence, the energy released in kilocalories is 9.42 kcal.

Find more on unit conversion at: brainly.com/question/141163

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8 0
2 years ago
Why material selection is important to design and manufacturing?​
Darina [25.2K]

Answer:

You want your product to be as strong and as long lasting as possible. There are also the safety implications to consider. You see, dangerous failures arising from poor material selection are still an all too common occurrence in many industries.

Explanation:

5 0
3 years ago
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If voltage , V = 100 + 6 volt and current , I = 10+ 0.2 A , then find <br> percentage error in R.
Akimi4 [234]

Explanation:

As we know, resistance is the ratio of voltage used and current flowing through the circuit. So,

<h3>R = V/I</h3>

By error calculation

<h3>∆R/R = [(∆V/V)100] + [(∆I/I)100]</h3>

V = 100 ± 6% V

I = 10 ± 0.2% A

∆R/R= (5/100)×100 + (0.2/10)×100

∆R/R=5+2=7%

<h2>So, percentage error in resistance (R) = ± 7%.</h2>
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3 years ago
The pressure in a section of horizontal pipe with a diameter of 2.5 cm is 139 kPa. Water ï¬ows through the pipe at 2.9 L/s. If t
My name is Ann [436]

Answer:

d = 2*0.87 = 1.75 cm

Explanation:

by using flow rate equation to determine the  speed in larger pipe

\phi =\pi r^2 v

v = \frac{\phi}{\pi r^2}

  = \frac{2900 cm^3/s}{3.14(1.25cm)^2}

= 591.10 cm/s

 = 5.91 m/s

by Bernoulli's EQUATION

p1 +\frac{1}{2} \rho v1^2 = p2 +\frac{1}{2} \rho v2^2

139000+ \frac{1}{2}*1000*5.91^2 = 101000 +\frac{1}{2}*1000* v2^2

solving for v2

v2 = 10.53 m/s

diameter can be determine by using flow rate equation

q = v \pi r^2

r^2 = \frac{q}{\pi v}

     = \frac{2900}{3.14*1053}

r = 0.87 cm

d = 2*0.87 = 1.75 cm

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